Answer: The distance of Observer A from the radio antenna is what fraction of the distance of Observer B from the radio antenna?
It is 1/4.
Step-by-step explanation:
We know that the intensity of electromagnetic waves decreases with the radius squared, this means that we can write a simple relation as:
Intensity(r) = A/r^2
Observer A measures 16 the intensity of observer B.
if Ia is the intensity that observer A measures and Ib is the intensity that observer B measures, we have that:
Ia = 16Ib
A/(ra)^2 = 16*A/(rb)^2
1/(ra)^2 = 16/(rb)^2
rb^2 = 16*ra^2
and we know that 16 = 4*4 = 4^2
rb^2 = (4*ra)^2
then rb = 4*ra
this means that the distance between observer B and the antenna is equal to 4 times the distance between observer A and the antenna.
The fraction is ra = rb/4
The distance of
Observer A from the radio antenna is what fraction of the distance of Observer B from the radio antenna?
It is 1/4.
Answer:True
Step-by-step explanation:
Answer:
219.6
Step-by-step explanation:
small basket:
0.55×288
=158.4
big basket:
0.85x72
=61.2
add up:
219.6
Answer: the constant proportionality is 1.5 x X = y
Step-by-step explanation:
Answer:
Step-by-step explanation:
2v+27=75
2v=75 - 27
2v=48
v= 24 visits
So, she needs 24 visits
