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BabaBlast [244]
2 years ago
9

Suppose that two small cities have the same longitude, which gives the east-west position of a point on Earth's surface. One has

latitude 23 degrees north, and the other has latitude 47 degrees. Assume Earth is a sphere with the a radius of 6,380km. Find the distance between the cities to the nearest kilometer.
_______km

Rewrite the arc length formula for an angle measure x given in radians, and simplify.

L=_________

Mathematics
1 answer:
wel2 years ago
6 0

Answer:

Distance between A and B is 2672 km.

Step-by-step explanation:

Since one city B is having latitude of 23° and other town is having latitude of 47°.Radius of Earth has been given as 6380 km.

Therefore arc A from x-axis will be A = 2πr(∅/360) = 2×3.14×6380×(47/360)

= 5230.90 km

Now arc B from x-axis = 2πr(∅'/360) = 2×3.14×6380(23/360) = 2559.80 km

Therefore distance between them = 5230.9-2559.8 = 2671.9 ≅ 2672 km

Now we will rewrite the arc length formula in radians.

arc A = r×(∅×π/180)

arc A = 6380×(47×π/180) = 1665.9π

arc B = 6380×(23×π/180) = 815.22π    

Now the distance between A and B =  850.68π

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kiruha [24]

Answer:

-2

Step-by-step explanation:

The first equation simplifies to -2x+8 so p should be replaced with -2

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3 years ago
A girl found dress fo £65.50 and there was an 15% sale on
Alika [10]

Answer: $65.50 - 15% = 55.675


Step-by-step explanation:

Conversion a decimal number to a fraction: 65.50 = 655

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2 · 20

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= 2227

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The common denominator you can calculate as the least common multiple of the both denominators - LCM(2, 40) = 40

4 0
3 years ago
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PRECALC QUESTION! Convert the polar representation of this complex number into its standard form: z = 2(cos 11pi/6+ i sin 11pi/6
Tanzania [10]
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\end{cases}\implies a+bi
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2cos\left( \frac{11\pi }{6} \right)+2sin\left( \frac{11\pi }{6} \right)\ i\implies 2\cdot \cfrac{\sqrt{3}}{2}+2\cdot \cfrac{-1}{2}\ i\implies \sqrt{3}-1i
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One card is drawn at random from a deck of 52 cards. The first card is not replaced, and a second card is drawn. (Enter your pro
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Answer:

We have a 52 card deck:

a. Find the probability that both cards are clubs.

The probability of drawing a club will be equal to the quotient between the number of clubs in the deck divided by the total number of cards in the deck.

We initially have 13 clubs and 52 cards, then the probability of drawing a club in the first draw is:

p1 = 13/52.

Now the probability of drawing a club in the second draw will be:

p2 = 12/51

Where each number is decreased by one because we already drew a card, and that card was a club.

Then the probability of both events happening will be equal to the product of the individual probabilities:

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b. Find the probability that the first card is a spade and the second is a club.

Same as before, the probability of first drawing a spade is:

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This case differs from the prior one because for the second draw we have 13 clubs in the deck, and as we already drew one card (that was not a club) the total number of cards in the deck is 51.

Now the joint probability will be:

P = p1*p2 = (13/52)*(13/51) = 0.064

3 0
2 years ago
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