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djyliett [7]
3 years ago
7

Josie can solve 4/3 rubix cubes in 1/6 of an hour. How many rubix cubes can she solve an in hour please help

Mathematics
1 answer:
777dan777 [17]3 years ago
3 0

Answer:

5

Step-by-step explanation:

So 1/6 of an hour is 10 minutes and 3/4 of a Rubiks cube is technically 1 1/4 so in an hour she can solve five in an hour

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Adjacent Angles:<br><br>Answer:​
lakkis [162]

Hey there!

Adjacent angles are two angles that are connecting, or adjoining. They have a common vertex and a common side, but they DO NOT overlap.

Hope it helps and have a great day!!!!

5 0
3 years ago
Dr. Johnson treated 1134 patients in 63 days.
Alchen [17]

Answer:

D= 18

Step-by-step explanation:

She treated 18 people on the average because 1134 dived by 63 is exactly 18.

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8 0
3 years ago
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A 40-m-long chain hangs vertically from a cylinder attached to a winch. Assume there is no friction in the system and the chain
daser333 [38]

Answer:

a) W₁ = 78400 [J]

b)Wt = 82320 [J]  

Step-by-step explanation:

a) W = ∫ f*dl      general expression for work

If we have a chain with density of 10 Kg/m, distributed weight would be

9.8 m/s² * 10 kg   = mg

Total length of th chain is 40 m, and the function of y at any time is

f(y) = (40 - y ) mg   where ( 40 - y ) is te length of chain to be winded

At the beggining we have to wind 40 meters   y = 0 at the end of the proccess  y = 40 and there is nothing to wind then:

f(y) = mg* (40 - y )

W₁ =  ∫f(y) * dy    ⇒ W₁ = ∫₀⁴⁰ mg* (40 - y ) dy  ⇒ W₁ = mg [ ∫₀⁴⁰ 40dy - ∫₀⁴⁰ ydy

W₁ = mg [ 40*y |₀⁴⁰   -  1/2 * y²  |₀⁴⁰    ⇒  W₁ = mg* [ 40*40 - 1/2 (40)² ]

W₁ = mg * [1/2]     W₁ = 10*9,8* ( 800 )

W₁ = 78400 [J]

b) Now we can calculate work to do if we have a 25 block and the chain is weightless

W₂ = ∫ mg* dy     ⇒    W₂  = ∫₀⁴⁰ mg*dy   ⇒    W₂  = mg y |₀⁴⁰

W₂ = mg* 40   = 10*9.8* 40  

W₂ = 3920 [J]

Total work

Wt = W₁  +  W₂        ⇒    Wt = 78400 + 3920

Wt = 82320 [J]

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