All categories

2 years ago

HELP ASAP PLEASE A LOT OF POINTS!!! I WILL 5 STAR YOU IF RIGHT

Mathematics

1 answer:

Vlad1618 [11]2 years ago

5 0

ANSWER:

Let T be the number of hours Yoko worked as a tutor this month.

So, the expression becomes

(13t + 8)x = 96

You might be interested in

There are 273 students in the 7th grade. If the

Elanso [62]

Answer:

Each teacher will have 21 students

Step-by-step explanation:

273 divded by 21 = 21

4 0

2 years ago

Read 2 more answers

On Monday, Takira counted 75 splatters of bird droppings on her car. On Tuesday afternoon, she counted 21 more. What is the perc

Law Incorporation [45]

Answer:

28%

Step-by-step explanation:

percent change in the number of bird droppings = increase in splatters / splatters counted on Monday x 100

$\frac{21}{75}$ x 100 = 28%

3 0

2 years ago

The perimeter of a rectangle is (10x2).if it's width is (2x-1),which expression represents the length

alexandr402 [8]

Answer: b. 3x + 2

Step-by-step explanation:

2l + 2w = p

2l + 2(2x - 1) = 10x + 2

2l + 4x - 2 = 10x + 2

2l = 6x + 4

l = 3x + 2

4 0

3 years ago

Round this number to the nearest tenth 4.9675

MatroZZZ [7]

Add half a tenth.
.. 4.9675 +0.05 = 5.0175
Throw away all the digits to the right of the tenths digit.
.. 5.0

Your rounded number is 5.0

8 0

3 years ago

The volume V of an ice cream cone is given by V = 2 3 πR3 + 1 3 πR2h where R is the common radius of the spherical cap and the c

Nuetrik [128]

Answer:

The change in volume is estimated to be 17.20 $\rm{in^3}$

Step-by-step explanation:

The linearization or linear approximation of a function $f(x)$ is given by:

$f(x_0+dx) \approx f(x_0) + df(x)|_{x_0}$ where $df$ is the total differential of the function evaluated in the given point.

For the given function, the linearization is:

$V(R_0+dR, h_0+dh) = V(R_0, h_0) + \frac{\partial V(R_0, h_0)}{\partial R}dR + \frac{\partial V(R_0, h_0)}{\partial h}dh$

Taking $R_0=1.5$ inches and $h=3$ inches and evaluating the partial derivatives we obtain:

$V(R_0+dR, h_0+dh) = V(R_0, h_0) + \frac{\partial V(R_0, h_0)}{\partial R}dR + \frac{\partial V(R_0, h_0)}{\partial h}dh\\V(R, h) = V(R_0, h_0) + (\frac{2 h \pi r}{3} + 2 \pi r^2)dR + (\frac{\pi r^2}{3} )dh$

substituting the values and taking $dx=0.1$ and $dh=0.3$ inches we have:

$V(R_0+dR, h_0+dh) =V(R_0, h_0) + (\frac{2 h \pi r}{3} + 2 \pi r^2)dR + (\frac{\pi r^2}{3} )dh\\V(1.5+0.1, 3+0.3) =V(1.5, 3) + (\frac{2 \cdot 3 \pi \cdot 1.5}{3} + 2 \pi 1.5^2)\cdot 0.1 + (\frac{\pi 1.5^2}{3} )\cdot 0.3\\V(1.5+0.1, 3+0.3) = 17.2002\\\boxed{V(1.5+0.1, 3+0.3) \approx 17.20}$

Therefore the change in volume is estimated to be 17.20 $\rm{in^3}$

4 0

2 years ago