Answer:
404 cm³ Anyway... Look down here for my explanation.
Step-by-step explanation:
Let's Draw a line from the center of the circle to one of the ends of the chord (water surface) and another to the point at greatest depth on your paper. A right-angled triangle is formed too. The Length of side to the water-surface is 5 cm, the hospot is 7 cm.
We Calculate the angle θ in the corner of the right-angled triangle by: cos θ = 5/7 ⇒ θ = cos ˉ¹ (5/7)
44.4°, so the angle subtended at the center of the circle by the water surface is roughly 88.8°
The area shaded will then be the area of the sector minus the area of the triangle above the water in your diagram.
Shaded area 88.8/360*area of circle - ½*7*788.8°
= 88.8/360*π*7² - 24.5*sin 88.8°
13.5 cm²
(using area of ∆ = ½.a.b.sin C for the triangle)
Volume of water = cross-sectional area * length
13.5 * 30 cm³
404 cm³
3 divide by 5 is 0.6 and you move the decimal two places to the right and your percentage is 60%
Answer:
b = 6
Step-by-step explanation:
18 = 3b
3b = 18
b = 18/3
<em><u>b = 6 </u></em>
Answer:
The correct answer is:
D) Q(2,1) R(3,-4) S(5,-3) T(4,0)
Step-by-step explanation:
When you reflect over the x-axis the vertices of the parallelogram, the y -coordinates is multiplying by -1.
Then the new coordinates of the parallelogram are:
Q(2,-1) R(3,-4) S(5,-3) T(-4,0)
