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The value of ∠BAC in the isosceles triangle is 9.7°
<h3>Cosine rule</h3>
Cosine rule is used to show the relationship between the sides and angles of a triangle. It is given by:
a² = b² + c² - 2bc*cos(A)
where a, b, c are the sides of the triangle and A, B, C are the angles opposite the sides.
AB = AC = 1185 (isosceles), BC = 200, let ∠BAC = x°, hence:
200² = 1185² + 1185² - 2(1185)(1185)cos(x)
2(1185)(1185)cos(x) = 2808450
cos(x) = 0.9857
x = 9.7°
The value of ∠BAC in the isosceles triangle is 9.7°
Find out more on Cosine rule at: brainly.com/question/7872492
The absolute value makes the -8 into a positive 8, then you subtract the 8 on both sides, giving you your answer 7. (Since 15-8=7)
