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3 years ago

11

ANSWER FAST PLZ 25 POINTS!!!!!!!!!!

1 answer:

katovenus [111]3 years ago

6 0

Answer:

25.21 sq yd

Step-by-step explanation:

the equation is 2r(3.14)

4x2=8

8x3.14=25.12

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What is the distance between (-3, 4) and (-3, 10)?

xxTIMURxx [149]

Answer:

6 is the the distance between the points

5 0

3 years ago

The volume V of an ice cream cone is given by V = 2 3 πR3 + 1 3 πR2h where R is the common radius of the spherical cap and the c

Nuetrik [128]

Answer:

The change in volume is estimated to be 17.20 $\rm{in^3}$

Step-by-step explanation:

The linearization or linear approximation of a function $f(x)$ is given by:

$f(x_0+dx) \approx f(x_0) + df(x)|_{x_0}$ where $df$ is the total differential of the function evaluated in the given point.

For the given function, the linearization is:

$V(R_0+dR, h_0+dh) = V(R_0, h_0) + \frac{\partial V(R_0, h_0)}{\partial R}dR + \frac{\partial V(R_0, h_0)}{\partial h}dh$

Taking $R_0=1.5$ inches and $h=3$ inches and evaluating the partial derivatives we obtain:

$V(R_0+dR, h_0+dh) = V(R_0, h_0) + \frac{\partial V(R_0, h_0)}{\partial R}dR + \frac{\partial V(R_0, h_0)}{\partial h}dh\\V(R, h) = V(R_0, h_0) + (\frac{2 h \pi r}{3} + 2 \pi r^2)dR + (\frac{\pi r^2}{3} )dh$

substituting the values and taking $dx=0.1$ and $dh=0.3$ inches we have:

$V(R_0+dR, h_0+dh) =V(R_0, h_0) + (\frac{2 h \pi r}{3} + 2 \pi r^2)dR + (\frac{\pi r^2}{3} )dh\\V(1.5+0.1, 3+0.3) =V(1.5, 3) + (\frac{2 \cdot 3 \pi \cdot 1.5}{3} + 2 \pi 1.5^2)\cdot 0.1 + (\frac{\pi 1.5^2}{3} )\cdot 0.3\\V(1.5+0.1, 3+0.3) = 17.2002\\\boxed{V(1.5+0.1, 3+0.3) \approx 17.20}$

Therefore the change in volume is estimated to be 17.20 $\rm{in^3}$

4 0

3 years ago

Can I have help with the question

sleet_krkn [62]

Answer:

Midpoint = (3.5, 4.5)

Perpendicular bisector = y = $\frac{7}{9}$ x + $\frac{16}{9}$

Step-by-step explanation:

[] We can solve this using the midpoint formula:

-> See attached

[] Plug-in our coordinates and solve:

$(\frac{7+0}{2} ,\frac{0+9}{2} )=(\frac{7}{2} ,\frac{9}{2} )=(3.5,4.5 )$

[] Now we will find the slope to solve for the perpendicular bisector.

-> We will use slope-intercept form, see attached

$\frac{9-0}{0-7}=\frac{9}{-7}$

-> The slopes of two perpendicular lines are negative reciprocals of each other, so $\frac{7}{9}$ will be the slope of or perpendicular bisector

-> Now we can solve for the equation by using y – y1 = m ( x – x1), were y1 and x1 are the coordinates of our midpoint

y - 4.5 = $\frac{7}{9}$ (x-3.5)

y - 4.5 = $\frac{7}{9}$ x- $\frac{49}{18}$

y = $\frac{7}{9}$ x- $\frac{49}{18}$ + 4.5

y = $\frac{7}{9}$ x + $\frac{16}{9}$

Have a nice day!

I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

6 0

2 years ago

Pls help answer that shows work will get brainliest

hichkok12 [17]

The anwser to the problem is C.

7 0

3 years ago

Vector v has a direction of (5,3) find the direction angle for v to the nearest degree

Vesnalui [34]

Answer:

$31^{\circ}$

Step-by-step explanation:

We have been given that vector v has a direction of (5,3). We are asked to find direction angle for v to nearest degree.

We know that direction of vector with components $(a,b)$ can be determined by $\theta=\text{tan}^{-1}(\frac{b}{a})$ .

Upon substituting the components of given vector in above formula, we will get:

$\theta=\text{tan}^{-1}(\frac{3}{5})$

$\theta=30.9637565^{\circ}$

Upon rounding to nearest degree, we will get:

$\theta\approx 31^{\circ}$

Therefore, the direction angle for vector v is 31 degrees.

3 0

3 years ago