Ask question

Ask question

All categories

2 years ago

5

Keaton received his allowance for the week on Friday. He spent 2/6 of his allowance on a movie ticket in 2/8 of his allowance at

the concession stand. What fraction is Lowndes to Kuehn spin at the movies total simplify possible.

1 answer:

motikmotik2 years ago

3 0

Answer:

dfgggyyhyyyyyyyhyhhhgggfhhtff

You might be interested in

Find f(2) if f(x) = (x + 1)2.<br> 9<br> 6<br> 5

zhannawk [14.2K]

6 just trust me bro I’m a major in math

8 0

3 years ago

The lateral area of the prism is 240 square inches. Find the total surface area.

e-lub [12.9K]

Answer:

Its C, 288 square inches

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

IM RUNNING OUT IF TIME CAN SOMEONE PLEASE HELP

Elenna [48]

Answer:

the third option

Step-by-step explanation:

hope this helps! have a good day and stay safe!

3 0

3 years ago

A tank contains 30 lb of salt dissolved in 500 gallons of water. A brine solution is pumped into the tank at a rate of 5 gal/min

Dmitry [639]

At any time $t$ (min), the volume of solution in the tank is

$500\,\mathrm{gal}+\left(5\dfrac{\rm gal}{\rm min}-5\dfrac{\rm gal}{\rm min}\right)t=500\,\mathrm{gal}$

If $A(t)$ is the amount of salt in the tank at any time $t$ , then the solution has a concentration of $\dfrac{A(t)}{500}\dfrac{\rm lb}{\rm gal}$ .

The net rate of change of the amount of salt in the solution, $A'(t)$ , is the difference between the amount flowing in and the amount getting pumped out:

$A'(t)=\left(5\dfrac{\rm gal}{\rm min}\right)\left(\left(2+\sin\dfrac t4\right)\dfrac{\rm lb}{\rm gal}\right)-\left(5\dfrac{\rm gal}{\rm min}\right)\left(\dfrac{A(t)}{50}\dfrac{\rm lb}{\rm gal}\right)$

Dropping the units and simplifying, we get the linear ODE

$A'=10+5\sin\dfrac t4-\dfrac A{10}$

$10A'+A=100+50\sin\dfrac t4$

Multiplying both sides by $e^{10t}$ allows us to identify the left side as a derivative of a product:

$10e^{10t}A'+e^{10t}A=\left(100+50\sin\dfrac t4\right)e^{10t}$

$\left(e^{10}tA\right)'=\left(100+50\sin\dfrac t4\right)e^{10t}$

$e^{10t}A=\displaystyle\int\left(100+50\sin\dfrac t4\right)e^{10t}\,\mathrm dt$

Integrate and divide both sides by $e^{10t}$ to get

$A(t)=10-\dfrac{200}{1601}\cos\dfrac t4+\dfrac{8000}{1601}\sin\dfrac t4+Ce^{-10t}$

The tanks starts off with 30 lb of salt, so $A(0)=30$ and we can solve for $C$ to get a particular solution of

$A(t)=10-\dfrac{200}{1601}\cos\dfrac t4+\dfrac{8000}{1601}\sin\dfrac t4+\dfrac{32,220}{1601}e^{-10t}$

6 0

3 years ago

3. Find the measure of side DF. See image below.

ad-work [718]

Answer:

d. 5.25

Step-by-step explanation:

make it into two fractions: 6/8 = x/7

solve for x by cross multiplying.

4 0

3 years ago