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3 years ago

Given: ΔABC, AB ≅ BC BE− median of ΔABC m∠ABE = 40°30' Find: m∠ABC, m∠FEC

Mathematics

2 answers:

Nikitich [7]3 years ago

8 0

I think angle abc is 80° and angle fec is 90°

Explanation:

Since angle abe is 40° just double it to get abc

And fec is just a 90° angle

monitta3 years ago

3 0

Answer:

m∠ABC = 81 degrees m∠FEC = 90 degrees

Step-by-step explanation:

You might be interested in

How do u simplify 3/30

sukhopar [10]

$\bf \cfrac{3}{30}\implies \cfrac{3\cdot 1}{3\cdot 10}\implies \cfrac{3}{3}\cdot \cfrac{1}{10}\implies 1\cdot \cfrac{1}{10}\implies \cfrac{1}{10}$

8 0

4 years ago

Given: ∆SPM, PK⊥ SM SP = 25, SM = 28, PK = 9 Find: m∠S, m∠M, PM

nevsk [136]

Answer:

∠S = 21.10°

∠M = 79.45°

PM = 9.16

Step-by-step explanation:

Here Pythagorean theorem and trigonometry suffice to solve our problem.

From the Pythagorean theorem we get:

$KM^2+9^2=PM^2$ and

$(25-KM)^2+9^2=25^2.$

We solve for $KM$ in the second equation and get:

$(25-KM)=\sqrt{25^2-9^2}$

$\therefore KM=25-\sqrt{25^2-9^2} =\boxed{1.68}$

Now since

$SK+KM=25\\\\ SK=\boxed{23.32}$

Therefore

${\angle}S=Tan^{-1}(\frac{PK}{SK}) = Tan^{-1}(\frac{9}{23.32})=21.10^o$

and

${\angle}M=Tan^{-1}(\frac{PK}{KM}) = Tan^{-1}(\frac{9}{1.68})=79.45^o.$

And finally again from the Pythagorean theorem:

$PM^2=PK^2+KM^2=9^2+1.68^2$

$\therefore PM=\sqrt{9^2+1.68^2} =9.16.$

Thus,

∠S = 21.10°

∠M = 79.45°

PM = 9.16.

7 0

4 years ago

you plan to buy a bicycle that will cost at least 180. you have saved 38 and your parents have given you 50. how much more money

shutvik [7]

Answer:

$92

Step-by-step explanation:

add what you saved and the parents gave you
subtract that by 180
$92

4 0

3 years ago

Evaluate the expression shown 6(14+8)12

Nady [450]

Answer:

1584

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Help ASAP! question in pic! will give brainliest!

serious [3.7K]

I think it’s 2
Hope that helped sorry if it’s wrong

8 0

3 years ago