1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zlopas [31]
2 years ago
11

Which item is not part of a college application

Computers and Technology
1 answer:
olga_2 [115]2 years ago
4 0

Answer:

Explanation:

application form and any fees

You might be interested in
Under the ____________________, federal agencies must 1) review their IT systems for privacy risks, 2) post privacy policies on
nadya68 [22]

Answer:

E-Government Act of 2002.

Explanation:

The E-Government Act of 2002 is a statute of the United States of America which was enacted by the 107th U.S Congress on the 17th of December, 2002. The E-Government Act of 2002 was signed into law to facilitate the management and promotion of the US government processes and services, as well as enhance transparency and accountability between the government and the public through the application of internet-based information technology.

Under the E-Government Act of 2002, federal agencies must;

1. Review their IT systems for privacy risks.

2. Post privacy policies on their websites.

3. Post machine-readable privacy policies on their websites.

4. Report privacy activities.

3 0
2 years ago
Create a program which will input data into a pipe one character at a time. Count the number of characters as they are written i
LenKa [72]

Answer:

a)

#include<stdio.h>

#include<stdlib.h>

#include<fcntl.h>

#include<unistd.h>

 

#define BUFSIZE 16

int main(){

   //pipe descriptors

   char msg[BUFSIZE];

   char buf[BUFSIZE];

   int pipefd[2];

   if(pipe(pipefd) == -1){

       //pipe creation error

       perror("pipe");

       exit(EXIT_FAILURE);

   }

   //pipe creation successfull

   //write four messages

   sprintf(msg , "apple");

   write(pipefd[1], msg, BUFSIZE);

   printf("Written %s\n", msg);

   sprintf(msg , "boy");

   write(pipefd[1], msg, BUFSIZE);

   printf("Written %s\n", msg);

   sprintf(msg , "cat");

   write(pipefd[1], msg, BUFSIZE);

   printf("Written %s\n", msg);

   sprintf(msg , "dog");

   write(pipefd[1], msg, BUFSIZE);

   printf("Written %s\n", msg);

   //read

   read(pipefd[0], buf, BUFSIZE);

   printf("Read: %s\n", buf);

   read(pipefd[0], buf, BUFSIZE);

   printf("Read: %s\n", buf);

   read(pipefd[0], buf, BUFSIZE);

   printf("Read: %s\n", buf);

   read(pipefd[0], buf, BUFSIZE);

   printf("Read: %s\n", buf);

   close(pipefd[0]);

   close(pipefd[1]);

   return 0;

}

(b)

#include<stdio.h>

#include<stdlib.h>

#include<fcntl.h>

#include<unistd.h>

#include<wait.h>

#define BUFSIZE 16

int main(){

   //pipe descriptors

   char msg[BUFSIZE];

   char buf[BUFSIZE];

   int pipefd[2];

   if(pipe(pipefd) == -1){

       //pipe creation error

       perror("pipe");

       exit(EXIT_FAILURE);

   }

   //pipe creation successfull

   //write four messages

   if(fork() == 0){

       //this is child

       //close unused write end

       close(pipefd[1]);

       read(pipefd[0], buf, BUFSIZE);

       printf("This is child process reading first message. Content is %s\n", buf);

       read(pipefd[0], buf, BUFSIZE);

       printf("This is child process reading second message. Content is %s\n", buf);

       read(pipefd[0], buf, BUFSIZE);

       printf("This is child process reading third message. Content is %s\n", buf);

       read(pipefd[0], buf, BUFSIZE);

       printf("This is child process reading fourth message. Content is %s\n", buf);

       close(pipefd[0]);

       //exit from child

       exit(EXIT_SUCCESS);

   }

   //this is parent process

   //close unused read end

   close(pipefd[0]);

   sprintf(msg , "apple");

   printf("This is parent process. Writing first message into pipe\n");

   write(pipefd[1], msg, BUFSIZE);

   sprintf(msg , "boy");

   printf("This is parent process. Writing second message into pipe\n");

   write(pipefd[1], msg, BUFSIZE);

   sprintf(msg , "cat");

   printf("This is parent process. Writing third message into pipe\n");

   write(pipefd[1], msg, BUFSIZE);

   sprintf(msg , "dog");

   printf("This is parent process. Writing fourth message into pipe\n");

   write(pipefd[1], msg, BUFSIZE);

   close(pipefd[1]);

   //wait for child

   wait(NULL);

   return 0;

}

(c)

#include<stdio.h>

#include<stdlib.h>

#include<fcntl.h>

#include<unistd.h>

#include<sys/wait.h>

#include<sys/types.h>

#include<signal.h>

typedef struct sigaction Sigaction;

unsigned long long size = 0;

void alarmhandler(int sig){

   //alarm fired writing blocked

   printf("Write blocked after %llu characters\n", size);

   exit(EXIT_SUCCESS);

}

int main(){

   //pipe descriptors

   int pipefd[2];

   if(pipe(pipefd) == -1){

       //pipe creation error

       perror("pipe");

       exit(EXIT_FAILURE);

   }

   //install handler

   sigset_t mask , prev;

   sigemptyset(&mask);

   sigaddset(&mask , SIGALRM);

   sigprocmask(SIG_BLOCK , &mask , &prev);

   Sigaction new_action;

   sigemptyset(&new_action.sa_mask);

   new_action.sa_flags = SA_RESTART;

   new_action.sa_handler = alarmhandler;

   sigaction(SIGALRM , &new_action , NULL);

   sigprocmask(SIG_SETMASK , &prev, NULL);

   while(1){

     

       //print size on multiple of 4

       if(size != 0 && size % 1024 == 0){

           printf("%llu characters in pipe\n", size);

       }

       //reset previous alarm

       alarm(0);

       //set new alarm for 5 seconds

       alarm(5);

       //write to pipe one character

       write(pipefd[1], "A", sizeof(char));

       size++;

   }

   return 0;

}

Explanation:

Output for a, b, c are pasted accordingly

4 0
3 years ago
Information that has been analyzed and refined so that it is useful to policymakers in making decisions; specifically, decisions
denis-greek [22]

Answer:

Intelligence

Explanation:

Intelligence is the product resulting from the collection, collation, evaluation, analysis, integration, and interpretation of collected information. It is a specialised information product that provides an adversary with information required to further its national interests. One of the most important functions of intelligence is the reduction of the ambiguity inherent in the observation of external activities.rations.  

In most cases, the development of an intelligence product involves collecting information from a number of different sources. In some cases, information may be disseminated immediately upon collection based upon operational necessity and potential impact on current operations.

Strategic intelligence provides policy makers with the information needed to make national policy or decisions of long-lasting importance. Strategic intelligence collection often requires integrating information concerning politics, military affairs, economics, societal interactions, and technological developments. It typically evolves over a long period of time and results in the development of intelligence studies and estimates.

Operational intelligence is concerned with current or near-term events. It is used to determine the current and projected capability of a program or operation on an ongoing basis and does not result in long-term projections. Most intelligence activities support the development of operational intelligence.

8 0
3 years ago
JAVA PROGRAMMING
VashaNatasha [74]

Answer:

See explaination

Explanation:

import java.util.Scanner;

public class GtldValidation {

public static void main (String [ ] args) {

Scanner scnr = new Scanner(System.in);

// Define the list of valid core gTLDs

String [ ] validCoreGtld = { ".com", ".net", ".org", ".info" };

// FIXME: Define an array named validRestrictedGtld that has the names

// of the restricted domains, .biz, .name, and .pro

String [] validRestrictedGtld={".biz",".name",".pro"};

String inputName = "";

String searchName = "";

String theGtld = "";

boolean isValidDomainName = false;

boolean isCoreGtld = false;

boolean isRestrictedGtld = false;

int periodCounter = 0;

int periodPosition = 0;

int i = 0;

System.out.println("\nEnter the next domain name (<Enter> to exit): ");

inputName = scnr.nextLine();

while (inputName.length() > 0) {

searchName = inputName.toLowerCase();

isValidDomainName = false;

isCoreGtld = false;

isRestrictedGtld = false;

// Count the number of periods in the domain name

periodCounter = 0;

for (i = 0; i < searchName.length(); ++i) {

if (searchName.charAt(i) == '.') {

++periodCounter;

periodPosition = i;

}

}

// If there is exactly one period that is not at the start

// or end of searchName, check if the TLD is a core gTLD or a restricted gTLD

if ((periodCounter == 1) &&

(searchName.charAt(0) != '.') &&

(searchName.charAt(searchName.length() - 1) != '.')) {

isValidDomainName = true;

}

if (isValidDomainName) {

// Extract the Top-level Domain name starting at the period's position. Ex:

// If searchName = "example.com", the next statement extracts ".com"

theGtld = searchName.substring(periodPosition);

i = 0;

while ((i < validCoreGtld.length) && (!isCoreGtld)) {

if(theGtld.equals(validCoreGtld[i])) {

isCoreGtld = true;

}

else {

++i;

}

}

// FIXME: Check to see if the gTLD is not a core gTLD. If it is not,

// check to see whether the gTLD is a valid restricted gTLD.

// If it is, set isRestrictedGtld to true

}

System.out.print("\"" + inputName + "\" ");

if (isValidDomainName) {

System.out.print("is a valid domain name and ");

if (isCoreGtld) {

System.out.println("has a core gTLD of \"" + theGtld + "\".");

}

else if (isRestrictedGtld) {

System.out.println("has a restricted gTLD of \"" + theGtld + "\".");

}

else {

System.out.println("does not have a core gTLD."); // FIXME update message

}

}

else {

System.out.println("is not a valid domain name.");

}

System.out.println("\nEnter the next domain name (<Enter> to exit): ");

inputName = scnr.nextLine();

}

return;

}

}

8 0
3 years ago
Which results are expected in a personality test but not a skills assessment?
dimaraw [331]

Answer:

openness, conscientiousness, extraversion

Explanation:

A personality test is defined as a test that is used to assess the human personality. It is designed as the techniques to measure characteristics patterns of the traits that various people shows at different situations or environments.

A skill assessment test is used to test the abilities and the skill sets of people to perform a particular tasks given to them. It is measuring the knowledge and skills of a person.

The personality test are carried out to test how human behave and what traits they show in certain conditions. Thus openness, extra version and conscientiousness are some of the traits that people usually shows in a personality test. Thus they are the results that are expected by an individual of a personality test.

6 0
2 years ago
Other questions:
  • Which term refers to an interface between HTML elements and JavaScript program code that allows JavaScript code to manipulate HT
    12·1 answer
  • Does an android tablet have a hard drive
    7·1 answer
  • Write a program that reads numbers from a file (or allow user to input data) and creates an ordered binary tree. The program sho
    8·1 answer
  • An access control system that grants users only those rights necessary for them to perform their work is operating on which secu
    6·1 answer
  • Write a program that reads in 10 numbers and displays the number of distinct numbers and the distinct numbers in their input ord
    14·1 answer
  • How can I make [ print(3 * x) ] into a functional python code?
    8·1 answer
  • If a system's instruction set consists of an 8-bit opcode, what is the maximum number of output signal lines required for the co
    13·1 answer
  • EDI, ________, smart cards, and digital certificates are designed to support safe and secure online transactions.
    8·1 answer
  • What is the full form of Computer?<br>​
    5·1 answer
  • Can you help me solve this challenging activity?
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!