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Hatshy [7]
3 years ago
15

Question is attached as image, please help :>

Computers and Technology
1 answer:
harkovskaia [24]3 years ago
3 0

Answer:

Proved

Explanation:

Given

X = (a.\bar b)+(\bar a.b)

(a + b)\ .  \frac{}{a.b}

Required

Find out why they represent the same

To do this, we simplify either (a + b)\ .  \frac{}{a.b} or X = (a.\bar b)+(\bar a.b)

In this question, I will simplify (a + b)\ .  \frac{}{a.b}

Apply de morgan's law

(a + b)\ .  \frac{}{a.b} = (a + b) . (\bar a + \bar b)

Apply distribution property

(a + b)\ .  \frac{}{a.b} = a.\bar a + a.\bar b + \bar a . b + b . \bar b

To simplify, we apply the following rules:

a.\bar a = 0 --- Inverse law

b.\bar b = 0 --- Inverse law

So, the expression becomes

(a + b)\ .  \frac{}{a.b} = 0 + a.\bar b + \bar a.b + 0

(a + b)\ .  \frac{}{a.b}  = a.\bar b + \bar a.b

Rewrite as:

(a + b)\ .  \frac{}{a.b}  = (a.\bar b)+(\bar a.b)

From the given parameters:

X = (a.\bar b)+(\bar a.b)

This implies that:

(a + b)\ .  \frac{}{a.b} when simplified is X or (a.\bar b)+(\bar a.b)

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Define a void function that calculates the sum (+), difference (-), product (*), quotient (/), and modulus (%) of two integer nu
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Answer:

#include <iostream>

using namespace std;

void multipurpose(int &num1,int &num2,int &add,int &subt,int &multi,int &divi,int &modulo )

{

   add=num1+num2;//adding two numbers...

   subt=abs(num1-num2);//subtracting two numbers...

   multi=num1*num2;//multiplying two numbers...

   divi=num1/num2;//Finding quotient of two numbers...

   modulo=num1%num2;//Finding modulo of two numbers...

}

void print(int add,int sub,int divi,int multi,int modulo) //function to print the values.

{

   cout<<"The addition is "<<add<<endl<<"The subtraction is "<<sub<<endl

   <<"The quotient is "<<divi<<endl<<"The multiplication is "<<multi<<endl

   <<"The modulus is "<<modulo<<endl;

}

int main() {

   int a,b,sum=0,mult=0,divi=0,sub=0,modulo=0;

   cin>>a>>b;

   multipurpose(a,b,sum,sub,mult,divi,modulo);

   print(sum,sub,divi,mult,modulo);

return 0;

}

Enter the numbers

12 12

The addition is 24

The subtraction is 0

The quotient is 1

The multiplication is 144

The modulus is 0

Explanation:

I have created a function multipurpose that has a argument list of two numbers ,and variables for addition,subtraction,multiplication,Division,Modulus and these all are passed by reference.Since the function is of type void so it cannot return anything so the only way to store the result is by passing the variables to store the results by  reference.

The other function print has the arguments of all the results here you can pass them by value or by reference because you only need to print the results.

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Answer:

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Any cute boy wants to talk with me?
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no

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no

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