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Andreyy89
3 years ago
12

How do you solve the absolute value equation |2x+6|-3=13 using one negative and one positive​

Mathematics
2 answers:
Amiraneli [1.4K]3 years ago
6 0

Answer:

x=5,-11

Step-by-step explanation:

Mars2501 [29]3 years ago
5 0

Answer:

x = 5, -11.

Step-by-step explanation:

|2x+6|-3=13

|2x+6| = 16

2x +6 = 16 or 2x + 6 = -16

2x = 10 or 2x = -22.

x = 5, -11.

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A number is chosen at random from 1 to 50. Find the probability of selecting numbers less than 35
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Answer:

3?

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Mary has completed 8 problems of her 20 question test. How much of the test has she completed in fraction form (simplity!)
allochka39001 [22]

Answer:

2/5

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<img src="https://tex.z-dn.net/?f=2x%5E2%2B5x%2B3%3D0" id="TexFormula1" title="2x^2+5x+3=0" alt="2x^2+5x+3=0" align="absmiddle"
melamori03 [73]

Answer:

x=-\frac{3}{2},-1

Step-by-step explanation:

2x^2+5x+3=0

Split the second term (5x) into two terms. Multiply the coefficient of the first term (2) by the constant term (3):

2*3=6

Find which two numbers add up to 5 and multiply into 6:

3+2=5\\3*2=6\\3,2

Split 5x as the sum of 3x and 2x:

2x^2+3x+2x+3

Now factor out a common term for the first 2 terms:

2x^2+3x\\x(2x+3)

And do the same for the last 2 terms:

2x+3\\1(2x+3)

Re-insert:

x(2x+3)+1(2x+3)=0

Factor out the common term 2x+3 and insert the values in front of the parentheses (x and 1):

(2x+3)(x+1)=0

Separate the parentheses and equal them to 0. Solve for x:

2x+3=0\\2x+3-3=0-3\\2x=-3\\\\\frac{2x}{2}=\frac{-3}{2}\\\\  x=-\frac{3}{2}

and

x+1=0\\x+1-1=0-1\\x=-1

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3 years ago
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RUDIKE [14]

pt1= (10,12)

pt2= (10,-8)

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distance = √ (x1 - x2)² + (y2 - y1)²

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=√ (0)² + (-20)²

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=√400

=20 units

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3 years ago
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