Answer:
The larger acute angle is equal to 50.8 degrees.
Step-by-step explanation:
Let's solve for both of the acute angles for the purpose of checking our work at the end with angle A being the top angle and angle B being the one on the base of the triangle (that's not the 90 degrees one). Determining whether to use sin/cos/tan comes from SOH-CAH-TOA.
A = cos^-1 (2√6/2√15)
However, you need to move the radical out of the denominator by multiplying √15 to the numerator and denominator. You should come up with (2√90)/30. So,
A = cos^-1 (2√90/30) = 50.768 degrees.
B = sin^-1 (2√90/30) = 39.231 degrees.
Now, we can check the work by adding the 2 angles to 90 and, if it comes to 180, it's right.
cos^-1 (2√90/30) + sin^-1 (2√90/30) + 90 = 180.
If you have any questions on where I got a formula or any step, feel free to ask in the comments!
Answer:
False
Step-by-step explanation:
can you please rotate the picture
Please consider the complete question.
A parking lot in the shape of a trapezoid has an area of 12,052.1 square meters. The length of one base is 82.4 meters and the length of the base is 108.6 meters. What is the width of the parking lot
We will use area of trapezoid to formula to solve our given problem.
, where
a and b represents parallel sides of trapezoid,
h = height of trapezoid.
Width of the trapezoid will be equal to height.
Upon substituting our given values in above formula, we will get:
Therefore, the width of the parking lot is 126.2 meters.
Yes it can you can use this website to draw a triangle
https://www.geogebra.org/m/JT5UmZ8w
