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3 years ago

Find the circumference and area of the circle. Use 3.14 for π. Round to the nearest hundredth if necessary.

Mathematics

2 answers:

BARSIC [14]3 years ago

4 0

Answer:

81.64

Step-by-step explanation:

densk [106]3 years ago

4 0

Answer:

Step-by-step explanation:

Please be explicit in labeling the radius. I will assume y ou meant r = 13 m.

Circumference formula: C = 2πr; area formula: A = πr²

Here, with r = 13 m, C = 2π(13 m) = 26π m = C = 81.68 m

and

with r = 13 m, A = π(13 m)^2 = 169π = A = 530.93 m^2

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Answer:

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Step-by-step explanation:

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3 years ago

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Answer:

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3 years ago

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Step-by-step explanation:

When you put something in parenthesis by a number, your multiplying each individual number by the number outside of parenthesis. Therefore, 5(2) = 10 and 5(7) = 35 and that equals 45, and 5(2+7) you distribute the 5 to both numbers and get 10+35 which equals 45 aswell.

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3 years ago

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3 years ago

A deck of 52 cards contains 12 picture cards. If the 52 cards are distributed in a random manner among four players in such a wa

Mkey [24]

Answer:

The probability that each player will receive three picture cards = 0.0324

Step-by-step explanation:

As given,

A deck of 52 cards contains 12 picture cards

Remaining card = 52 - 12 = 40

So,

Total number of ways in which 12 picture card is distributed = $\frac{12!}{3! 3! 3! 3!}$

Now,

The Total number of ways in which Remaining cards are distributed = $\frac{40!}{10! 10! 10! 10!}$

So,

Total number of ways of getting 3 picture card and remaining card = $\frac{12!}{3! 3! 3! 3!}$ × $\frac{40!}{10! 10! 10! 10!}$

= $\frac{12! 40!}{(3!)^{4} (10!)^{4} }$

Now,

Total number of ways to distribute 52 cards so that each people get 13 card = $\frac{52!}{13! 13! 13! 13!} = \frac{52!}{ (13!)^{4} }$

∴ The probability = $\frac{\frac{12! 40!}{(3!)^{4} (10!)^{4} }}{\frac{52!}{(13!)^{4} }}$

= $\frac{12! 40!}{(3!)^{4} (10!)^{4} }$ × $\frac{(13!)^{4} }{ 52! }$

= $\frac{12! 40!}{(3!)^{4} (10!)^{4} }$ × $\frac{(13.12.11.10!)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41.40! }$

= $\frac{12!}{(3!)^{4} }$ × $\frac{(13.12.11)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41}$

= $\frac{479,001,600}{(6)^{4} }$ × $\frac{(1716)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41}$

= 0.0324

∴ we get

The probability that each player will receive three picture cards = 0.0324

6 0

3 years ago