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aleksklad [387]
3 years ago
14

Enter the value that is missing

Mathematics
1 answer:
masha68 [24]3 years ago
3 0
I think it’s 15.75. Because: 2•1.05=2.10. 5•1.05= 5.25. 20•1.05= 21.00. So, 15•1.05= 15.75.
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Prove that sin3a-cos3a/sina+cosa=2sin2a-1
Sloan [31]

Answer:

\frac{sin(3a)-cos(3a)}{sin(a)+cos(a)} =2sin(2a)-1

Step-by-step explanation:

we are given

\frac{sin(3a)-cos(3a)}{sin(a)+cos(a)} =2sin(2a)-1

we can simplify left side and make it equal to right side

we can use trig identity

sin(3a)=3sin(a)-4sin^3(a)

cos(3a)=4cos^3(a)-3cos(a)

now, we can plug values

\frac{(3sin(a)-4sin^3(a))-(4cos^3(a)-3cos(a))}{sin(a)+cos(a)}

now, we can simplify

\frac{3sin(a)-4sin^3(a)-4cos^3(a)+3cos(a)}{sin(a)+cos(a)}

\frac{3sin(a)+3cos(a)-4sin^3(a)-4cos^3(a)}{sin(a)+cos(a)}

\frac{3(sin(a)+cos(a))-4(sin^3(a)+cos^3(a))}{sin(a)+cos(a)}

now, we can factor it

\frac{3(sin(a)+cos(a))-4(sin(a)+cos(a))(sin^2(a)+cos^2(a)-sin(a)cos(a)}{sin(a)+cos(a)}

\frac{(sin(a)+cos(a))[3-4(sin^2(a)+cos^2(a)-sin(a)cos(a)]}{sin(a)+cos(a)}

we can use trig identity

sin^2(a)+cos^2(a)=1

\frac{(sin(a)+cos(a))[3-4(1-sin(a)cos(a)]}{sin(a)+cos(a)}

we can cancel terms

=3-4(1-sin(a)cos(a))

now, we can simplify it further

=3-4+4sin(a)cos(a))

=-1+4sin(a)cos(a))

=4sin(a)cos(a)-1

=2\times 2sin(a)cos(a)-1

now, we can use trig identity

2sin(a)cos(a)=sin(2a)

we can replace it

=2sin(2a)-1

so,

\frac{sin(3a)-cos(3a)}{sin(a)+cos(a)} =2sin(2a)-1


7 0
3 years ago
Read 2 more answers
What is a point-slope equation of the line with slope -10 that goes through the point (1,4)
KatRina [158]
\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad \qquad \qquad 
% slope  = m
slope =  m\implies -10
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-4=-10(x-1)
8 0
2 years ago
Read 2 more answers
Screenshoted question below
kumpel [21]

Answer:

y=x+4

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
(7,5), (r,9) m=6<br><br> What is r?
Igoryamba

Answer:

The answer is that r = 7/6

Step-by-step explanation:

Given point: (7, 5)

Given slope: m = 6

Use the point slope form of the equation:

y - y1 = m(x - x1)

y - 5 = 6(x - 7)

y - 5 = 6x - 7

y = 6x + 2

Now, find r for the point (r, 9) by substitution:

9 = 6x + 2

6x + 2 = 9

6x = 7

x = 7/6

Proof:

y = 6x + 2

f(x) = 6x + 2

f(7/6) = 6(7/6) + 2

= 42/6 + 2

= 7 + 2 = 9, giving (7/6, 9). r = 7/6

Hope this helps! Have a great day!

4 0
3 years ago
NEED HELP ASAP PLEASE !!
Alexxandr [17]

Answer:

A, C, E

Step-by-step explanation:

The square root of 10 is approximately 3.16, which is greater than pi which is equal to about 3.14, which shows that C is correct as well. The square root of 11 is 3.31, and the square root of 5 added to the square root of 6 is equal to about 3.69, which is greater than the square root of 11.

6 0
3 years ago
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