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aleksklad [387]
3 years ago
14

Enter the value that is missing

Mathematics
1 answer:
masha68 [24]3 years ago
3 0
I think it’s 15.75. Because: 2•1.05=2.10. 5•1.05= 5.25. 20•1.05= 21.00. So, 15•1.05= 15.75.
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Can you guys help me out
marusya05 [52]

Answer:

a. S = 3n + 2

b. There while be 62 squares.

Step-by-step explanation:

We know the first term of this sequence is 5. To figure out the equation, subtract the following term from the previous. Do you see a common difference?

8 - 5 = 3

11 - 8 = 3

14 - 11 = 3

We're seeing a constant difference of 3 (which makes this an arithmetic sequence), but the first term is 5. That mean something is being added to make the first term 5. Subtract 3 from 5 to get 2. This means 2 is being added to every multiple of 3, which leads us to the equation: S = 3n + 2.

To find the 20th term of this sequence, substitute n for 20 and do the operations.

S = 3(20) + 2

<em>Multiply 3 by 20, then add 2.</em>

S = 62

The 20th term will have 62 squares.

7 0
3 years ago
Help me plz i dont know to do this
Inessa05 [86]
You gotta multiply and then round it to the nearest tenth hope it worked!
3 0
3 years ago
Read 2 more answers
What is a constant rate of change key characteristics
aalyn [17]
The key is to do it on ur own
4 0
3 years ago
The lifetimes of a certain type of light bulbs follow a normal distribution. If approximately 2.5% of the bulbs have lives excee
spin [16.1K]

Answer:

Mean = 339 hours

Standard deviation = 54 hours

Step-by-step explanation:

We are given that approximately 2.5% of the bulbs have lives exceeding 445 hours

So,P(x>445) = 0.025

P(x<445) =1- 0.025 =0.975

 z value for 0.975 is 1.96

Formula : z=\frac{x-\mu}{\sigma}

So, 1.96=\frac{445-\mu}{\sigma}

1.96 \sigma =445-\mu--A

Now we are given that  approximately 16% have lives exceeding 393 hours,

So,P(x>393) = 0.16

P(x<393) =1- 0.16 =0.84

 z value for 0.84 is 1

Formula : z=\frac{x-\mu}{\sigma}

So, 1=\frac{393-\mu}{\sigma}

1 \sigma =393-\mu ---B

Solve A and B

Substitute the value of \sigmafrom B in A

1.96 (393 -\mu) =445-\mu

770.28 -1.96\mu=445-\mu

770.28 -445=1.96\mu-\mu

325.28=0.96\mu

\frac{325.28}{0.96}=\mu

338.83=\mu

Substitute the value in B

\sigma =393-338.83

\sigma =54.17

So, mean = 339 hours

Standard deviation = 54 hours

5 0
4 years ago
What is the GCF of 49 and 98
zheka24 [161]

Answer:

The other app my teacher told me to use to get the answer after i figure out says it is 1

Step-by-step explanation:

3 0
3 years ago
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