Complete question :
61 randomly selected students were asked the number of pairs of shoes they have. Let X represent the number of pairs of shoes. The results are as follows:
Pairs of Shoes4__5__6__7 __8 __9 __10 __11
Frequency : _ 8 _ 8 __5 _ 5 _ 9 __11 __7 ___8
Answer:
Mean = 7.64 ;
Median = 8
Q1 = 5
Q3 = 9
Atleast 10 pairs = 24.6
76% is equivalent to
Step-by-step explanation:
Round all your answers to 4 decimal places where possible.
10
The mean is:
Σfx /Σf
((8*4)+(5*8)+(6*5)+(7*5)+(8*9)+(9*11)+(10*7)+11*8)) ÷ (8+8+5+5+9+11+7+8) = 7.64
The median is:
0.5(n+1)th observation
n = frequency = 61
0.5(61 +1) = 1/2 * 62 = 31st observation
= 8
First quartile:
0.25(n+1)th observation
n = frequency = 61
0.25(61 +1) = 1/4 * 62 = 15.5
(15 + 16)th observation ÷ 2 = (5 + 5) / 2 = 5
The sample standard deviation is:
The third quartile is:
0.75(n+1)th observation
n = frequency = 61
0.75(61 +1) = 1/4 * 62 = 46.5
(46 + 47)th observation ÷ 2 = (5 + 5) / 2 = 9
What percent of the respondents have at least 10 pairs of Shoes? %
(7 + 8) / 61 = 15 / 61 = 0.246
76% of all respondents have fewer than how many pairs of Shoes?
(76 / 100) * 61
0.76 * 61
= 46.36
(46th + 47th)
(9 + 10) = 19 /2 = 9.5 = 10
