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3 years ago

I need help please!:D

Mathematics

2 answers:

Semmy [17]3 years ago

5 0

Answer:

The answer would be: <u>75</u>

Step-by-step explanation:

15×5=75

we ignore the 4 because it's irrelevant.

I hope this helps :)

True [87]3 years ago

4 0

5×15= 75 the 4 days is irrelevant

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Suppose a and b are the solutions to the quadratic equation 2x^2-3x-6=0. Find the value of (a+2)(b+2).

KonstantinChe [14]

Answer:

(a+2)(b+2) = 4

Step-by-step explanation:

We are given the following quadratic equation:

$2x^2-3x-6=0$

Let a a and b be the solution of the given quadratic equation.

Solving the equation:

$2x^2-3x-6=0\\\text{Using the quadratic formula}\\\\x = \dfrac{-b \pm \sqrt{b^2-4ac}}{2a}\\\\\text{Comparing the equation to }ax^2 + bx + c = 0\\\text{We have}\\a = 2\\b = -3\\c = -6\\x = \dfrac{3\pm \sqrt{9-4(2)(-6)}}{4} = \dfrac{3\pm \sqrt{57}}{4}\\\\a = \dfrac{3+\sqrt{57}}{4}, b = \dfrac{3-\sqrt{57}}{4}$

We have to find the value of (a+2)(b+2).

Putting the values:

$(a+2)(b+2)\\\\=\bigg(\dfrac{3+\sqrt{57}}{4}+2\bigg)\bigg(\dfrac{3-\sqrt{57}}{4}+2\bigg)\\\\=\bigg(\dfrac{11+\sqrt{57}}{4}\bigg)\bigg(\dfrac{11-\sqrt{57}}{4}\bigg)\\\\=\dfrac{121-57}{156} = \dfrac{64}{16} = 4$

3 0

3 years ago

I don't know what to do or how to do it

OleMash [197]

Answer:

i think you multiple the measure

3 0

3 years ago

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Maggie has a food scale with a digital display that shows the weight as a decimal number. The recipe she is using calls for ingr

strojnjashka [21]

Put the decimal over 100 and get rid of the decimal

8 0

4 years ago

A segment with endpoints A (3, 4) and C (5, 11) is partitioned by a point B such that AB and BC form a 2:3 ratio. Find B.

Dima020 [189]

Answer:

(3.8, 6.8)

Step-by-step explanation:

Point B:

Has coordinates (x,y)

AB and BC form a 2:3 ratio.

This means that:

$B - A = \frac{2}{2+3}(C - A)$

$B - A = \frac{2}{5}(C - A)$

We apply this both for the x-coordinate and for the y-coordinate.

x-coordinate:

x-coordinate of A: 3

x-coordinate of C: 5

x-coordinate of B: x

$B - A = \frac{2}{5}(C - A)$

$x - 3 = \frac{2}{5}(5 - 3)$

$x - 3 = \frac{4}{5}$

$x = 0.8 + 3 = 3.8$

y-coordinate:

y-coordinate of A: 4

y-coordinate of C: 11

y-coordinate of B: y

$B - A = \frac{2}{5}(C - A)$

$y - 4 = \frac{2}{5}(11 - 4)$

$y - 4 = \frac{14}{5}$

$y = 2.8 + 4 = 6.8$

Thus the correct answer is:

(3.8, 6.8)

7 0

3 years ago

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URGENT! WILL GIVE BRAINLY FOR CORRECT ANSWER

Minchanka [31]

Answer:

sorry if im wrong i think wrong numbers. plz check

Step-by-step explanation:

The center of dilation of the question is (-4,-3) .

let say that

x0=-4

y0=-3

Label the image A'B'C'

The new coordinate would be

A(-4,-1)

x=4

y=-1

x'=x0+ 2(x - x0)

x'= -4+ 2(-4 +4)

x'=-4

y'=y0+ 2(y - y0)

y'= -3+ 2(-1 +3)

y'=-3 +4= 1

______________________________

B(-4,-3)

x=-4

y=-3

x'=x0+ 2(x - x0)

x'= -4+ 2(-4 +4)

x'=-4

y'=y0+ 2(y - y0)

y'= -3+ 2(-3 +3)

y'=-3

______________________________

C(-1,-3)

x=-1

y=-3

x'=x0+ 2(x - x0)

x'= -4+ 2(-1 +4)

x'=-4 +6= 2

y'=y0+ 2(y - y0)

y'= -3+ 2(-3 +3)

y'=-3

A'(-4,1)

B'(-4,-3)

C'(2,-3)

3 0

3 years ago