Ok, so it seems to be the square root of the cube root of 2
we just convert to exponential
remember
and
![\sqrt[n]{x^m} =x^ \frac{m}{n}](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7Bx%5Em%7D%20%3Dx%5E%20%5Cfrac%7Bm%7D%7Bn%7D%20)
therfor
![\sqrt{ \sqrt[3]{2} }= \sqrt{2^ \frac{1}{3} } =( 2^ \frac{1}{3})^ \frac{1}{2} =2^ \frac{1}{6}](https://tex.z-dn.net/?f=%20%5Csqrt%7B%20%5Csqrt%5B3%5D%7B2%7D%20%7D%3D%20%5Csqrt%7B2%5E%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20%3D%28%202%5E%20%5Cfrac%7B1%7D%7B3%7D%29%5E%20%5Cfrac%7B1%7D%7B2%7D%20%3D2%5E%20%5Cfrac%7B1%7D%7B6%7D%20%20)
last choice is correct
The formula for percent of increase/decrease:
difference in original and new/original x 100
17926-12475/12475=
5451/12475=
.4369
x 100=
43.7% increase
Answer:
Suppose we have a random number A.
The multiplicative inverse of A is a number X such that:
A*X = 1
When we work with real numbers, X = 1/A
Then:
A*(1/A) = A/A = 1
This means that (1/A) is the multiplicative inverse of A.
Where we need to have A ≠ 0, because we can not divide by 0.
Now we want to find the multiplicative inverse of the numbers:
2: Here the inverse is (1/2) = 0.5
1/5: Here the inverse is (1/(1/5)) = (5/1) = 5
-4: Herre the inverse is (1/(-4)) = -(1/4) = -0.25
