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Verizon [17]
4 years ago
5

-8r - 2 + 7r= -9solve the equation. then check the solution

Mathematics
1 answer:
gulaghasi [49]4 years ago
8 0
The first step for solving this equation is to collect the like terms with an r variable.
-r - 2 = -9
Now move the constant to the right side of the equation and then change its sign.
-r = -9 + 2
Calculate the sum on the right side of the equals sign.
-r = -7
Then lastly,, change the signs on both sides of the equation to find your final answer.
r = 7
This means that the correct answer to your question is going to be r = 7.
We can check this by putting 7 where r is in the equation. This means that in order to check this,, our equation will change to the following:
-8(7) - 2 + 7(7) = -9
We will first start checking this by multiplying the first two numbers together.
-56 - 2 + 7(7) = -9
Now multiply the 7 by the number in the parenthesis.
-56 - 2 + 49 = -9
Now use addition and subtraction rules to calculate the expression on the left side of the equals sign.
-9 = -9
This tells us that the equality us true because both sides of the equation are identical.
Let me know if you have any further questions.
:)
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Consider the parabola r​(t)equalsleft angle at squared plus 1 comma t right angle​, for minusinfinityless thantless thaninfinity
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Given:-   r(t)=< at^2+1,t>  ; -\infty < t< \infty , where a is any positive real number.

Consider the helix parabolic equation :  

                                              r(t)=< at^2+1,t>

now, take the derivatives we get;

                                            r{}'(t)=

As, we know that two vectors are orthogonal if their dot product is zero.

Here,  r(t) and r{}'(t)  are orthogonal i.e,   r\cdot r{}'=0

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take t common in above equation we get,

t\cdot \left (2a^2t^2+2a+1\right )=0

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Since, for any positive value of a determinant is negative.

Therefore, there is no solution.

The only solution, we have t=0.

Hence, we have only one points on the parabola  r(t)=< at^2+1,t> i.e <1,0>




                                               




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