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Makovka662 [10]
3 years ago
15

7x + 9 = 10 - x please help meeeeeeee

Mathematics
2 answers:
nikklg [1K]3 years ago
8 0

Answer:

7x + 9 = 10 - x \\ (7 + 1)x = 10 - 9 \\ 8x = 1 \\ x =  \frac{1}{8}

Evgen [1.6K]3 years ago
6 0

Answer - x = 1/8

A brainliest for the answer will be apprecited

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Q3.
umka2103 [35]

Answer:

8.48%

Step-by-step explanation:

Bill's weight decreases from 64.8 kg to 59.3 kg.

We need to find the percentage decrease in Bill's weight. It can be calculated as follows :

\%=\dfrac{64.8 -59.3 }{64.8 }\times 100\\\\=8.48\%

So, the required decrease in percentage is 8.48%.

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3 years ago
I need help #16 an 17
Romashka [77]
Seventeen is :3 2/2
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which will increase the volume of a square pyramid more doubling the length of each side of tripling the height (hint test it wi
Furkat [3]
Im pretty sure it would be doubling the length of each side
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3 years ago
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If E F = 7 , A C = 16 , and A F = 9
Vilka [71]

Answers:

CB = 14

GF = 8

FB = 9

EF is parallel to CB

====================================

Explanations:

Points E and F are midpoints of their respective sides. They form the midsegment EF. Because EF is a midsegment, A midsegment is half the length of its parallel counterpart, so CB is two times longer than EF. If EF is 7 units long, then CB = 2*EF = 2*7 = 14

For similar reasons, GF is parallel to AC. If AC = 16, then half of that is GF = (1/2)*AC = 0.5*16 = 8.

FB = FA = 9 as these segments have the same single tickmark to indicate they are the same length

EF is parallel to CB because EF is a midsegment, and this is one of the properties of being a midsegment. We can show that quadrilateral EGBF is a parallelogram to help prove this.

8 0
3 years ago
A geometric series has second term 375 and fifth term 81 . find the sum to infinity of series .
Eduardwww [97]

Answer:  \bold{S_{\infty}=\dfrac{3125}{2}=1562.5}

<u>Step-by-step explanation:</u>

  a₁,  375,  a₃,   a₄,  81

First, let's find the ratio (r). There are three multiple from 375 to 81.

375r^3=81\\\\r^3=\dfrac{81}{375}\\\\\\r^3=\dfrac{27}{125}\qquad \leftarrow simplied\\\\\\\sqrt[3]{r^3} =\sqrt[3]{\dfrac{27}{125}}\\ \\\\r=\dfrac{3}{5}

Next, let's find a₁

a_1\bigg(\dfrac{3}{5}\bigg)=375\\\\\\a_1=375\bigg(\dfrac{5}{3}\bigg)\\\\\\a_1=125(5)\\\\\\a_1=625

Lastly, Use the Infinite Geometric Sum Formula to find the sum:

S_{\infty}=\dfrac{a_1}{1-r}\\\\\\.\quad =\dfrac{625}{1-\frac{3}{5}}\\\\\\.\quad =\dfrac{625}{\frac{2}{5}}\\\\\\.\quad = \dfrac{625(5)}{2}\\\\\\.\quad = \large\boxed{\dfrac{3125}{2}}

7 0
3 years ago
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