The side lengths are given in proportions which are 2:3:5:6. The perimeter is given as the sum of all the sides which is given as 48 cm. Using ratio and proportion, the sum of all the sides or the perimeter is proportional to the sum of all the fractions and the largest fraction is proportional to the longest side of the quadrilateral.

Let x be the longest side of the quadrilateral. The largest proportion is 6.
6/(2+3+5+6) = 6/16
6/16 = x/48

x= 18 cm. The longest side is 18 cm. The other sides are 6, 9, 15 using the other proportions.

5 0

3 years ago

Find the area of the triangle, i will give brainliest

GenaCL600 [577]

109
21.8x10=218
218 divided by 2 = 109

4 0

2 years ago

What is the answer to this 8(*/4 - 6)>4

nika2105 [10]

Answer:

first comment

Step-by-step explanation:

4 0

3 years ago

Two fractions have denominators of x^2+ 6x + 9 and x^2. What is the Least Common Denominator?

Gala2k [10]

SOLUTION

Write out the denominator of the fraction, we have

$\begin{gathered} x^2+6x+9 \\ \text{And } \\ x^2-9 \end{gathered}$

We want to obtain the least common denominator.

To do this, we need to factorize each of the expression given

$\begin{gathered} x^2+6x+9 \\ =x^2+3x+3x+9 \\ =x(x+3)+3(x+3) \\ =(x+3)(x+3) \end{gathered}$

Then we factorise the other fraction using difference of two square

$\begin{gathered} a^2-b^2=(a-b)(a+) \\ \text{Then} \\ x^2-9=x^2-3^2 \\ =(x-3)(x+3) \end{gathered}$

The the factorise expression becomes

$(x+3)(x+3)\text{ and (x-3)(x+3)}$

To obtain the least common denominator, we select the common factor and the product of the other factor,

Hence

$\begin{gathered} \text{common factor=(x+3)} \\ \text{The other factors are (x-3)(x+3)} \\ \text{Then } \\ \text{Least co}mmon\text{ denominator becomes } \\ (x+3)(x-3)(x+3) \end{gathered}$

Thus

The Least Common Denominator is (x +3)(x+3)(x-3) (Last Option )

5 0

1 year ago