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KATRIN_1 [288]
3 years ago
5

In how many ways can a

Mathematics
1 answer:
stiks02 [169]3 years ago
3 0

Answer:

59,280

Step-by-step explanation:

the answer is base in my previous learning.. hope it helps..

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Sally wants to buy an assortment of candy. She has $7 dollars she can spend in the candy store. The candy store sells chocolate
Tom [10]

Answer:

I found the table by an online search (it is below)

Sally has $7 to spend in candy.

The price of a chocolate bar is $1.50

The price of a lollipop is $0.75

The price of gumballs is $0.25

In the table, we have the following combinations.

a) 3 chocolate bars, 3 lollipops and 4 gumballs, the price is:

3*$1.50 + 3*$0.75 + 4*$0.25 = $7.75 (she can not buy this)

b) 3 chocolate bars and 4 gumballs, the price is:

3*$1.50 + 4*$0.25 = $5.50 (she can buy this)

c) 1 chocolate bar, 5 lollipops and 2 gumballs, the price is:

1*$1.50 + 5*$0.75 + 2*$0.25 =  $5.75 (she can buy this)

d) 2 chocolate bars, 2 lollipops and 8 gumballs, the price is:

2*$1.50 + 2*$0.75 + 8*$0.25 = $6.50 (she can buy this)

8 0
3 years ago
Will is buying a house for $185,000. He is financing $165,000 and obtained a 30-year, fixed-rate mortgage with a 6.725% interest
guajiro [1.7K]
<h3>Answer:  $1067.45</h3>

=================================================

Work Shown:

L = 165000 = loan amount or amount financed

r = 0.06725  = annual interest rate in decimal form

i = r/12 = 0.06725/12 = 0.005604167

i = 0.005604167 = approximate monthly interest rate in decimal form

n = number of months = 30*12 = 360 months

P = unknown monthly payment

--------------

Apply the monthly payment formula

P = (L*i)/( 1-(1+i)^(-n) )

P = (165000*0.005604167)/(1-(1+0.005604167)^(-360))

P = 1067.44636311118

P = 1067.45

6 0
3 years ago
David swam in 312 events during the last 6 years. He swam the same number of events each year.
natta225 [31]

Answer:

52

Step-by-step explanation:

Divide 312 by 6 to find the number of events he swam per year

5 0
2 years ago
Read 2 more answers
Pls, help me I don't understand! Very urgent!!!! (I have an attachment so you know what the problem looks like)
vredina [299]

1. A pair of supplementary angles: ∠IJH and ∠HJG, ∠IJH and ∠HJG

2. A pair of complementary angles: ∠JGK and ∠KGC, ∠FGE and ∠EGD

3. A pair of vertical angles: ∠AKB and ∠KJG , ∠IJH and ∠KJG

Solution:

<em>Two angles are said to be supplementary when they add up to 180°.</em>

We know that,

Sum of the adjacent angles in a straight line = 180°

∠IJK + ∠KJG = 180°

Therefore ∠IJK and ∠KJG are supplementary angles.

∠IJH + ∠HJG = 180°

Therefore ∠IJH and ∠HJG are supplementary angles.

<em>Two angles are said to be complementary when they add up to 90°.</em>

Given ∠CGD = 90°, ∠CGJ = 90°

∠JGK + ∠KGC = ∠CGJ

∠JGK + ∠KGC = 90°

Therefore ∠JGK and ∠KGC are complementary angles.

∠FGE + ∠EGD = 90°

Therefore ∠FGE and ∠EGD are complementary angles.

<em>If two lines are intersecting, then the angles opposite to vertical point are vertical angles and they are equal.</em>

∠AKB = ∠KJG (vertically opposite)

∠IJH = ∠KJG (vertically opposite)

5 0
3 years ago
Calcular la edades actuales de una madre y sus dos hijos sabiendo que hace 14 años la dad de la madre era 5
rodikova [14]

The present age of mother and her daughter respectively are; 40 and 10 years respectively.

<h3>How to Solve Algebra Word Problems?</h3>

Let x and y be the present age of mother and her daughter respectively.

Therefore;

x + y = 50

x = 50 − y     .....(1)

After 20 years, mother's age will be twice her daughter's age at the time. Thus;

x + 20 = 2(y + 20)

x − 2y = 20     .....(2)

Plugging eq 1 into eq 2 gives us;

50 − y − 2y = 20

3y = 30

y = 10

Thus;

x = 50 − 10

x = 40

Thus, the present age of mother and her daughter is 40 and 10 years respectively.

Translation of the question into English is;

The sum of the present ages of mother and her daughter is 50 years. After 20 years, mother's age will be twice her daughter's age at the time. Find their present ages.

Read more about Algebra Word Problems at; brainly.com/question/21405634

#SPJ1

6 0
2 years ago
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