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borishaifa [10]
3 years ago
13

Simplify (-a2b3)2(c2)0

Mathematics
2 answers:
Jobisdone [24]3 years ago
6 0
The correct answer is 
                                    <span>a4b<span>6 I think also your question is missed up next time fix it</span></span>
MariettaO [177]3 years ago
4 0
The expression simplified is
a^{2} b^{3} (2)c^{2} (0)
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What is 12/25 as a percent
mart [117]
12/25 is 48% becuase 12/25 is alao 48/100 because 12 x 4= 48 and 25 x 4= 100.
7 0
3 years ago
Read 2 more answers
A random sample of 20 recent weddings in a country yielded a mean wedding cost of $ 26,388.67. Assume that recent wedding costs
Makovka662 [10]

Answer:

a) 95% confidence interval for the mean​cost, μ​, of all recent weddings in this country = (22,550.95, 30,226.40)

.The​ 95% confidence interval is from $22,550.95 to $30,226.40.

b) For the interpretation of the result, option D is correct.

We can be​ 95% confident that the mean​ cost, μ​, of all recent weddings in this country is somewhere within the confidence interval.

c) Option B is correct.

The population mean may or may not lie in this​ interval, but we can be​ 95% confident that it does.

Step-by-step explanation:

Sample size = 20

Sample Mean = $26,388.67

Sample Standard deviation = $8200

Confidence Interval for the population mean is basically an interval of range of values where the true population mean can be found with a certain level of confidence.

Mathematically,

Confidence Interval = (Sample mean) ± (Margin of error)

Sample Mean = 26,388.67

Margin of Error is the width of the confidence interval about the mean.

It is given mathematically as,

Margin of Error = (Critical value) × (standard Error of the mean)

Critical value will be obtained using the t-distribution. This is because there is no information provided for the population mean and standard deviation.

To find the critical value from the t-tables, we first find the degree of freedom and the significance level.

Degree of freedom = df = n - 1 = 20 - 1 = 19.

Significance level for 95% confidence interval

(100% - 95%)/2 = 2.5% = 0.025

t (0.025, 19) = 2.086 (from the t-tables)

Standard error of the mean = σₓ = (σ/√n)

σ = standard deviation of the sample = 8200

n = sample size = 20

σₓ = (8200/√20) = 1833.6

99% Confidence Interval = (Sample mean) ± [(Critical value) × (standard Error of the mean)]

CI = 26,388.67 ± (2.093 × 1833.6)

CI = 26,388.67 ± 3,837.7248

99% CI = (22,550.9452, 30,226.3948)

99% Confidence interval = (22,550.95, 30,226.40)

a) 95% confidence interval for the mean​cost, μ​, of all recent weddings in this country = (22,550.95, 30,226.40)

.The​ 95% confidence interval is from $22,550.95 to $30,226.40.

b) The interpretation of the confidence interval obtained, just as explained above is that we can be​ 95% confident that the mean​ cost, μ​,of all recent weddings in this country is somewhere within the confidence interval

c) A further explanation would be that the population mean may or may not lie in this​ interval, but we can be​ 95% confident that it does.

Hope this Helps!!!

4 0
3 years ago
Does anyone know the answer? (It's not 0,4)
Murljashka [212]
I believe it would be any number that is within the darkest shaded area. (-4,1) seems like it would be correct.
6 0
3 years ago
Read 2 more answers
Estimate the quotient of 21.49 ÷ 3.76 using compatible numbers.
kvv77 [185]

The quotient of 21.49 ÷ 3.76 using compatible numbers is approximately 5.69

<h3>What are quotients?</h3>

Quotients are result derived from the ratio of two rational or integers. Given the expression

21.49 ÷ 3.76

Convert to fraction

21.49 ÷ 3.76 = 2140/100  ÷  376/100
21.49 ÷ 3.76 = 2140/376

21.49 ÷ 3.76 =  5.69

Hence the quotient of 21.49 ÷ 3.76 using compatible numbers is approximately 5.69

Learn more on quotient here: brainly.com/question/673545

#SPJ1

4 0
2 years ago
78 round to the nearest tenth
LenaWriter [7]
78 rounded to the nearest tenth is 80
3 0
3 years ago
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