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dlinn [17]
3 years ago
13

a sequence has a first term of 2 and a constant ratio of _3/2 what are the first five terms of the sequence

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
5 0
This is a geometric sequence with a=2, r= -3/2.
Therefore,
a₁ = 2
a₂ = 2*(-3/2) = -3
a₃ = 2*(-3/2)² = 9/2 = 4.5
a₄ = 2(-3/2)³ = -27/4 = -6.75
a₅ = 2(-3/2)⁴ = 81/8 = 10.125

Answer:
In fractions, the first five terms are
     2, -3, 9/2, -27/4, 81/8
In decimals, the first five terms are
     2.000, -3.000, 4.500, -6.750, 10.125


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1. It took Joseph 10 days, 21 hours, and 30 minutes to get from San Diego to Boston. How many hours did it take him? Show your w
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Point Q' is the image of Q(-7, -6) under the translation (x, y) + (x + 12, y + 8).
Lina20 [59]

Answer:

The co-ordinates of Q' is (5,2).

Step-by-step explanation:

Given:

Pre-image point

Q(-7,-6)

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(x,y)\rightarrow (x+12,y+8)

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Horizontal shift:

(x,y)\rightarrow (x+k,y)

when K>0 the point is translated k units to the right.

when K the point is translated k units to the left.

Vertical shift:

(x,y)\rightarrow (x,y+k)

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when K the point is translated k units down.

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Q'=(-7+12,-6+8)=(5,2)

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