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Vesnalui [34]
3 years ago
9

The sum of the square of two consecutive whole number is 25. Find the numbers

Mathematics
1 answer:
Gnom [1K]3 years ago
3 0
Don't you mean "the sum of the squares ..."?
The sum of the squares of two consecutive whole numbers is 25.  Find the numbers.  Let the first be represented by x and the second by x+1.
Then x^2+(x+1)^2=25.  Expanding, x^2+x^2+2x+1=25.
Rewriting this as a quadratic equation in standard form,

2x^2+2x+1=25, or 2x^2+2x-24=0.  Simplifying, x^2+x-12=0.
Factoring, (x-3)(x+4)=0.  Solving for x:  x-3=0, so x=3; x+4=0, so x=-4.
Choose the positive x value:  x=3.  Then the next consecutive number is 2+1=3+1=4.

Check:  Does 3^2 + 4^2 = 5^2 = 25?  Yes.
The numbers are 3 and 4.
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Family has an annual income of ​$23 comma 400. Of​ this, one fourth
denis23 [38]

Amount spent for food = $5850, housing = $4680, clothing = $2340, savings = $2600, taxes = $5850, expenses = $2080.

<u>Step-by-step explanation:</u>

Step 1:

Given details are Total Income = $23,400

Step 2:

Amount spent for food, F= 1/4th of 23,400 = 1/4 \times 23400

= $5850

Step 3:

Amount spent for housing, H = 1/5th of 23,400 = 1/5 \times23400

= $4680

Step 4:

Amount spent for clothing, C = 1/10th of 23,400 = 1/10 \times 23400 = $2340

Step 5:

Amount spent for savings, S = 1/9th of 13,400 = 1/9\times 23400 = $2600

Step 6:

Amount spent for taxes, T = 1/4th of 23,400 =  1/4 \times 23400 =$5850

Step 7:

Find amount spent on other expenses by totaling all expenditures and subtracting from the annual income.

Annual Income = F + H + C + S + T + E

Amount spent on other expenses, E = 23400 - (5850 + 4680 + 2340 + 2600 + 5850)

E = 23400 - 21320

E = $2080

5 0
3 years ago
Can you answer number 3, 4, and 5?<br> (Whoever is right gets brainliest)
valkas [14]

Answer:

3: 200, 200

4:800

5:400

Step-by-step explanation:

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3 0
3 years ago
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Find the solution of the system of equations.<br> −5x+5y=-10<br> 6x+5y=1
pickupchik [31]

Answer:

Step-by-step explanation:

Since you have

+

5

y

in one equation and

−

5

y

in the other equation, you can add both equations to cancel out the y terms and solve for x.

−

6

x

+

5

x

=

−

x

5

y

−

5

y

=

0

1

+

10

=

11

therefore

−

x

=

11

multiplying both sides by -1:

x

=

−

11

plugging this back into the first equation:

−

6

(

−

11

)

+

5

y

=

1

66

+

5

y

=

1

subtracting 66 from both sides:

5

y

=

−

65

divide both sides by 5:

y

=

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13

putting the x-values and y-values into one point gives:

(

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4 0
3 years ago
Read 2 more answers
23/7y state restrictions
qwelly [4]

The restrictions on the variable of the given rational fraction is y ≠ 0.

<h3>The types of numbers.</h3>

In Mathematics, there are six (6) common types of numbers and these include the following:

  • <u>Natural (counting) numbers:</u> these include 1, 2, 3, 4, 5, 6, .....114, ....560.
  • <u>Whole numbers:</u> these comprises all natural numbers and 0.
  • <u>Integers:</u> these are whole numbers that may either be positive, negative, or zero such as ....-560, ...... -114, ..... -4, -3, -2, -1, 0, 1, 2, 3, 4, .....114, ....560.
  • <u>Irrational numbers:</u> these comprises non-terminating or non-repeating decimals.
  • <u>Real numbers:</u> these comprises both rational numbers and irrational numbers.
  • <u>Rational numbers:</u> these comprises fractions, integers, and terminating (repeating) decimals such as ....-560, ...... -114, ..... -4, -3, -2, -1, -1/2, 0, 1, 1/2, 2, 3, 4, .....114, ....560.

This ultimately implies that, a rational fraction simply comprises a real number and it can be defined as a quotient which consist of two integers x and y.

<h3>What are restrictions?</h3>

In Mathematics, restrictions can be defined as all the real numbers that are not part of the domain because they produces a value of 0 in the denominator of a rational fraction.

In order to determine the restrictions for this rational fraction, we would equate the denominator to 0 and then solve:

23/7y;

7y = 0

y = 0/7

y ≠ 0.

Read more on restrictions here: brainly.com/question/10957518

#SPJ1

Complete Question:

State any restrictions on the variables 23/7y

4 0
2 years ago
Help me please o(* ̄▽ ̄*)ブ
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Answer:

Hey there!

Part a) Distance from Wrexham to Oswetry: 15 miles.

Part b) Ruthin to Oswestry: 33 miles.

Total distance travelled for Part b= 33(5), or 165 miles.

6 0
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