Answer: sin
= ±
Step-by-step explanation:
We very well know that,
cos2A=1−2sin²A
⟹ sinA = ±
As required, set A =
& cos a=
,thus we get
sin
=±
∴ sin
=±
= ±
since ,360° <
<450°
,180° <
<225°
Now, we are to select the value with the correct sign. It's is obvious from the above constraints that the angle a/2 lies in the III-quadrant where 'sine' has negative value, thus the required value is negative.
hope it helped!
A to the power of b
a^b
a = base
b = exponent
SO
10^243 or 10 to the power of 243.
You can use other numbers also.
Hope i helped!!
Answer:
b
Step-by-step explanation:
Answer:
173/1000
Step-by-step explanation: