You have to move the decimal point all the way to behind the 9.
You move it eleven places to the right.
The answer is
9.3 x 10^-11
To factor an expression, first you have to find the GCF or Greatest Common Factor of all of the pieces of the expression.
The GCF of 2y^2 and -4y is 2y
So, to factor this expression, we need to divide all of the pieces of the expression by the GCF.
2y(y-2)
2y^2 - 4y in completely factored form is 2y(y-2)
Answer:$570
Step-by-step explanation:If it is 900 for 2 walls, and they need 6 walls, then multiply 900 by 3. They would use 2700 bricks for 6 walls. Multiply 2700 by 0.10 to get the price for all the bricks, 270 dollars. If labor to build each wall costs 50 dollars then multiply that by 6 and add it to the 270 dollars. It costs 570 dollars to build 6 walls
Answer:
Most people found the probability of just stopping at the first light and the probability of just stopping at the second light and added them together. I'm just going to show another valid way to solve this problem. You can solve these kinds of problems whichever way you prefer.
There are three possibilities we need to consider:
Being stopped at both lights
Being stopped at neither light
Being stopped at exactly one light
The sum of the probabilities of all of the events has to be 1 because there is a 100% chance that one of these possibilities has to occur, so the probability of being stopped at exactly one light is 1 minus the probability of being stopped at both lights minus the probability of being stopped at neither.
Because the lights are independent, the probability of being stopped at both lights is just the probability of being stopped at the first light times the probability of being stopped at the second light. (0.4)(0.7) = 0.28
The probability of being stopped at neither is the probability of not being stopped at the first light, which is 1-0.4 or 0.6, times the probability of not being stopped at the second light, which is 1-0.7 or 0.3. (0.6)(0.3) = 0.18
Step-by-step explanation:
Answer:
Step-by-step explanation: