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Vanyuwa [196]
2 years ago
12

Which of the following is true regarding the sequence below?

Mathematics
2 answers:
babunello [35]2 years ago
6 0

Answer:

Option A

Step-by-step explanation:

7/12-5/12=2/12

=1/6 (shown)

kotegsom [21]2 years ago
3 0

Answer:

Option A

Step-by-step explanation:

Let's find common difference

\\ \sf\longmapsto \dfrac{7}{12}-\dfrac{5}{12}

\\ \sf\longmapsto \dfrac{7-5}{12}

\\ \sf\longmapsto \dfrac{2}{12}

\\ \sf\longmapsto \dfrac{1}{6}

Hence verified

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The perimeter of a rectangular garden is 62 feet( remember, perimeter= 2l + 2w where l is the length and w is the width). The le
Volgvan

Answer:

w=10 feet

l=21feet

Step-by-step explanation:

let width be x

p=2l+2w

p=62

so we form the equation

l=1+2x

w=x

2(1+2x)+2(x)=62

2+4x+2x=62

6x=60

x=10feet

w=10feet

l=1+2x

l=21feet

4 0
3 years ago
Someone can explain to me how I have to do this? please
frosja888 [35]

Answer:

A=r×r

64=r×rبالجذر

r=8

5 0
3 years ago
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Last week at Best Bargin, 75% of the computers sold were laptops. If 340 computers were sold last week, how many were laptops?
shusha [124]
75% of 340 is 85 so 85 laptops were sold at Best Bargin
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3 years ago
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Hello I need help with my homework if someone could help me and explain to me how this works that would be great thank you
Tatiana [17]

Answer:


Step-by-step explanation:

5. 17.25-8.25= 9

6. 7+8=15

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7 0
3 years ago
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g A popular theory is that presidential candidates have an advantage if they are taller than their main opponents. Listed are he
stira [4]

Answer:

Step-by-step explanation:

Corresponding heights of presidents and height of their main opponents form matched pairs.

The data for the test are the differences between the heights.

μd = the​ president's height minus their main​ opponent's height.

President's height. main opp diff

191. 166. 25

180. 179. 1

180. 168. 12

182. 183. - 1

197. 194. 3

180. 186. - 6

Sample mean, xd

= (25 + 1 + 12 - 1 + 3 + 6)/6 = 5.67

xd = 5.67

Standard deviation = √(summation(x - mean)²/n

n = 6

Summation(x - mean)² = (25 - 5.67)^2 + (1 - 5.67)^2 + (12 - 5.67)^2+ (- 1 - 5.67)^2 + (3 - 5.67)^2 + (- 6 - 5.67)^2 = 623.3334

Standard deviation = √(623.3334/6 sd = 10.19

For the null hypothesis

H0: μd ≥ 0

For the alternative hypothesis

H1: μd < 0

The distribution is a students t. Therefore, degree of freedom, df = n - 1 = 6 - 1 = 5

The formula for determining the test statistic is

t = (xd - μd)/(sd/√n)

t = (5.67 - 0)/(10.19/√6)

t = 1.36

We would determine the probability value by using the t test calculator.

p = 0.12

Since alpha, 0.05 < than the p value, 0.12, then we would fail to reject the null hypothesis.

Therefore, at 5% significance level, we can conclude that for the population of heights for presidents and their main​ opponents, the differences have a mean greater than 0 cm.

5 0
3 years ago
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