Answer:
Once the sun comes up, the sunlight excites the cold air in the first foot or so above the ground (which can be 10 or more degrees colder), which causes it to move around and mix into the next several feet of air. That “mixing upward” drops the temperature of the air at thermometer level.
Explanation:
Answer:
No of Moles in excess at the end of the reaction is 0.25 moles
Explanation:
AgNO3 + Mg3P2 → Ag3P + Mg(NO3)2
Balancing the equation we get
6AgNO3 + Mg3P2 → 2Ag3P + 3Mg(NO3)2
6 moles of AgNO3 needs 1 mole of Mg3P2
using unitary method
AgNO3 = 
1.5 AgNO3 =
= 1/4 = 0.25moles of Mg3P2
So 1.5 Moles of AgNO3 requires 0.25Mg3P2 for complete reaction but we have 0.5Moles of Mg3P2 available Therefore Mg3P2 is in excess
No of Moles in excess at the end of the reaction = 0.5 - 0.25 = 0.25moles
(3.500 mol MgO)(40.3044g MgO/1mol MgO)
=141.0654
Answer:
344.21 g/mol
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
Explanation:
<u>Step 1: Define</u>
Cr₂(SO₃)₃
<u>Step 2: Identify</u>
Molar Mass of Cr - 52.00 g/mol
Molar Mass of S - 32.07 g/mol
Molar Mass of O - 16.00 g/mol
<u>Step 3: Find</u>
Molar Mass of Cr₂(SO₃)₃ - 2(52.00) + 3(32.07) + 9(16.00) = 344.21 g/mol