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tekilochka [14]
3 years ago
8

An atom becomes negatively charged by

Chemistry
2 answers:
Firlakuza [10]3 years ago
7 0
<span>If the atom gains an electron, the atom becomes a negative ion.</span>
Pavlova-9 [17]3 years ago
4 0
If it gains a electron
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a faucet drips at a rate of 5.20 mL each minute. How many liters of water will the faucet lose in 72.0 hours? (1000 mL= 1 liter
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22.464 L in 72 hours
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3 years ago
Magnesium metal is added to excess acid to generate hydrogen gas, which is collected over water at 25.0°C (vapour pressure of wa
pentagon [3]

Answer:

Explanation:

PV / RT =  n , n is number of moles

Total pressure  = 96400 Pa

vapour pressure = 23.8 mm of Hg

= .0238 x 13.6 x 10³ x 10 Pa = 3236.8 Pa

Pressure of hydrogen gas P = 96400 - 3236.8

= 93163.2 Pa

n = 93163.2 x .0251 / 8.31 x 298

= .944 moles of hydrogen gas is produced

moles of magnesium reacted = .944

grams of magnesium reacted = .944 x 24 = 22.66 grams .

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3 years ago
As the organsims develops, its cells become -------
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It's cells become larger in numbers.
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4 years ago
Which change is an unlikely result of destruction of wetlands?
ArbitrLikvidat [17]

Answer:

D. Healthy fish populations

Explanation:

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7 0
2 years ago
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A sample of gas occupies a volume of 61.5 mL . As it expands, it does 130.1 J of work on its surroundings at a constant pressure
Lesechka [4]

Answer:

the final volume of the gas is V_2 = 1311.5 mL

Explanation:

Given that:

a sample gas has an initial volume of 61.5 mL

The workdone = 130.1 J

Pressure = 783 torr

The objective is to determine the final volume of the gas.

Since the process does 130.1 J of work on its surroundings at a constant pressure of 783 Torr. Then, the pressure is external.

Converting the external pressure to atm ; we have

External Pressure P_{ext}:

P_{ext} = 783 \ torr \times \dfrac{1 \ atm}{760 \ torr}

P_{ext} = 1.03 \ atm

The workdone W = P_{ext}V

The change in volume ΔV= \dfrac{W}{P_{ext}}

ΔV = \dfrac{130.1 \ J  \times \dfrac{1 \ L  \ atm}{ 101.325 \ J}  }{1.03 \ atm }

ΔV = \dfrac{1.28398717 }{1.03  }

ΔV = 1.25 L

ΔV = 1250 mL

Recall that the initial  volume = 61.5 mL

The change in volume V is \Delta V = V_2 -V_1

-  V_2= -  \Delta V  -V_1

multiply through by (-), we have:

V_2=   \Delta V+V_1

V_2 =  1250 mL + 61.5 mL

V_2 = 1311.5 mL

∴ the final volume of the gas is V_2 = 1311.5 mL

5 0
3 years ago
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