Answer keys ? With out that I can't answer it Lol!!
The ideal gas law states: ![PV=nRT](https://tex.z-dn.net/?f=PV%3DnRT)
If we put in the data.
![1\cdot7=n\cdot8.31\cdot294 \\n=\boxed{2.865\cdot10^{-3}mol}=\boxed{2.865mmol}](https://tex.z-dn.net/?f=%3C%2Fp%3E%3Cp%3E1%5Ccdot7%3Dn%5Ccdot8.31%5Ccdot294%20%5C%5C%3C%2Fp%3E%3Cp%3En%3D%5Cboxed%7B2.865%5Ccdot10%5E%7B-3%7Dmol%7D%3D%5Cboxed%7B2.865mmol%7D%3C%2Fp%3E%3Cp%3E)
Hope this helps.
r3t40
Answer:
25.42 atm
Explanation:
Data Given:
Volume of a gas ( V )= 2.00 L
temperature of a gas ( T ) = 310 K
number of moles (n) = 2 mol
Pressure of a gas ( P ) = to be find
Solution:
Formula to be used
PV= nRT
Rearrange the above formula
P = nRT / V . . . . . . . . . . (1)
Where R is ideal gas constant
R = 0.08205 L atm mol⁻¹ K⁻¹
Put values in equation 1
P = nRT / V
P = 2 mol x 0.08205 L atm mol⁻¹ K⁻¹ x 310 k / 2 L
P = 50.84 L atm / 2 L
P = 25.42 atm
P ressure of gas (P) will be = 25.42 atm