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Alex17521 [72]
3 years ago
5

Of the elements: b, c, f, li, and na. the element with the smallest ionization energy is

Chemistry
1 answer:
love history [14]3 years ago
8 0
B-  8.2980
C-  11.2603
F-  17.4228
Li-  5.3917
Na- 5.1391

I would say your answer is Na.
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Really need help with this<br> Will give brainliest to whoever has the correct answer
lukranit [14]

Answer:

a=0.4\ m/s^2

Explanation:

1. Given that,

Initial speed of a bicycle, u = 4 m/s

The final speed of a bicycle, v = 6 m/s

Time, t = 6 s

We need to find the acceleration of the bicycle. We know that, acceleration is    equal to the change in speed divided by time taken. So,

a=\dfrac{v-u}{t}\\\\a=\dfrac{6-4}{5}\\\\a=0.4\ m/s^2

So, the acceleration of the bicycle is equal to 0.4\ m/s^2.

5 0
3 years ago
What mass of copper is deposited when a current of 10.0a is passed through a solution of copper(ii) nitrate for 30.6 seconds?
asambeis [7]
Data Given:

Time = t = 30.6 s

Current = I = 10 A

Faradays Constant = F = 96500

Chemical equivalent = e = 63.54/2 = 31.77 g

Amount Deposited = W = ?

Solution:
             According to Faraday's Law,

                                          W  =  I t e / F

Putting Values,
 
                            W  =  (10 A × 30.6 s × 31.77 g) ÷ 96500

                            W  =  0.100 g

Result:
           0.100 g of Cu
²⁺ is deposited.
3 0
3 years ago
As the water velocity decreases, the size of the particles that the water can transport increases. True or false
tiny-mole [99]
The answer is False.
8 0
3 years ago
What is the distinction between magma and lava​
lesya692 [45]

Answer:

Scientists use the term magma for molten rock that is underground and lava for molten rock that breaks through the Earth's surface.

7 0
2 years ago
A chemist fills a reaction vessel with mercurous chloride solid, mercury (I) aqueous solution, and chloride aqueous solution at
makvit [3.9K]

Answer:

ΔG° = -533.64 kJ

Explanation:

Let's consider the following reaction.

Hg₂Cl₂(s) ⇄ Hg₂²⁺(aq) + 2 Cl⁻(aq)

The standard Gibbs free energy (ΔG°) can be calculated using the following expression:

ΔG° = ∑np × ΔG°f(products) - ∑nr × ΔG°f(reactants)

where,

ni are the moles of reactants and products

ΔG°f(i) are the standard Gibbs free energies of formation of reactants and products

ΔG° = 1 mol × ΔG°f(Hg₂²⁺) + 2 mol × ΔG°f(Cl⁻) - 1 mol × ΔG°f(Hg₂Cl₂)

ΔG° = 1 mol × 148.85 kJ/mol + 2 mol × (-182.43 kJ/mol) - 1 mol × (-317.63 kJ/mol)

ΔG° = -533.64 kJ

3 0
3 years ago
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