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madreJ [45]
3 years ago
13

An algorithm whose worst-case time complexity is bounded above by a polynomial function of its size is called a(n)

Computers and Technology
1 answer:
Sedaia [141]3 years ago
4 0

Answer:

polynomial-bounded algorithms

Explanation:

There are two algorithm complexities and they are time and space complexities. They can be denoted with the big-O notation. The big-o notation for a time and space complexity gets the worst-case time and space respectively.

The time complexity gets the measure of the execution time of an algorithm. When the time function is a polynomial ( k^n + k^n-1 ...) then the algorithm is said to be a polynomial-bounded algorithm.

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Creative Commons Question -- At home, you created a really great digital song, audio jingle, or music track using some software
galina1969 [7]
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Given the following declaration, what is the value of b[ 1 ][ 0 ]? int b[ 2 ][ 2 ] = { { 1 }, { 3 , 4 } };
slavikrds [6]

Based on the declaration "int b[ 2 ][ 2 ] = { { 1 }, { 3 , 4 } };" given, the value of b[ 1 ][ 0 ] is equal to 3.

<h3>What is Python?</h3>

Python can be defined as a high-level programming language that is designed and developed to build websites and software applications, especially through the use of dynamic commands (semantics), declarations, functions, and data structures.

<h3>What is an int?</h3>

Int is an abbreviation for an integer and it can be defined as a whole number that may either be positive, negative, or zero.

Based on the declaration "int b[ 2 ][ 2 ] = { { 1 }, { 3 , 4 } };" given, we can infer and logically deduce that the value of b[ 1 ][ 0 ] is equal to 3.

Read more on Python integers here: brainly.com/question/18761825

#SPJ1

8 0
2 years ago
Complete the do-while loop to output every number form 0 to countLimit using printVal. Assume the user will only input a positiv
elena-s [515]

Answer:

PART ONE

  1. import java.util.Scanner;
  2. public class CountToLimit {
  3.    public static void main(String[] args) {
  4.        Scanner scnr = new Scanner(System.in);
  5.        int countLimit = 0;
  6.        int printVal = 0;
  7.        // Get user input
  8.        System.out.println("Enter Count Limit");
  9.        countLimit = scnr.nextInt();
  10.        do {
  11.            System.out.print(printVal + " ");
  12.            printVal = printVal + 1;
  13.        } while ( printVal<=countLimit );
  14.        System.out.println("");
  15.        return;
  16.    }
  17. }

PART TWO

  1. import java.util.Scanner;
  2. public class NumberPrompt {
  3.    public static void main (String [] args) {
  4.        Scanner scnr = new Scanner(System.in);
  5.        System.out.print("Your number < 100: ");
  6.       int  userInput = scnr.nextInt();
  7.      do {
  8.           System.out.print("Your number < 100: ");
  9.           userInput = scnr.nextInt();
  10.       }while (userInput>=100);
  11.        System.out.println("Your number < 100 is: " + userInput);
  12.        return;
  13.    }
  14. }

Explanation:

In Part one of the question, The condition for the do...while loop had to be stated this is stated on line 14

In part 2, A do....while loop that will repeatedly prompt user to enter a number less than 100 is created. from line 7 to line 10

7 0
3 years ago
Term of The surroundings and conditions of your workplace
Ainat [17]

Answer:

what

Explanation:

uhh this isnt complete or something i dont know what this is im gonna answer it for the points

8 0
3 years ago
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