Answer:
TTppRR will produce TpR gametes. ttPPrr will produce tPr gametes.
Explanation:
Let us assume:
Normal tail : T, Tail less : t, Pale skin : P, Dark skin : p, Smooth skin : R, Rough skin : r
A pure-bred normal tail, dark skin, smooth skin mouse and a pure-bred mouse that is tail-less, pale skin, and rough skin crossed together then,
TTppRR x ttPPrr
One allele from every gene comes in a gamete thus, TTppRR will produce TpR gametes. ttPPrr will produce tPr gametes.
Answer:
Cellular respiration, which generates ATP in your cells, requires oxygen to take place, also, it generates CO2 as a waste product. The respiratory system allows oxygen to diffuse into your blood, and carbon dioxide to diffuse out. The blood then carries the oxygen to the cells, so cellular respiration to continue. When the blood reaches the cells, it also takes the carbon dioxide out of the cells, and carries it to the lungs to get rid of it.
<span>field of view is the correct answer</span>
Answer:
Replicated chromosomes at metaphase I = 66
Sister chromatids at metaphase I = 66 x 2 = 132
Sister chromatids at prophase II = 66
Chromosomes in each sperm cells = 33
Explanation:
Metaphase I of meiosis I would have 66 replicated chromosomes in the testicular cells of the bird. Each of the replicated chromosomes would have two sister chromatids. So, a total of 66 replicated chromosomes would have 66 x 2 = 132 sister chromatids.
Due to segregation of homologous chromosomes towards opposite poles in anaphase I, each daughter cell formed by the end of meiosis I would have 33 replicated chromosomes. So, each of the daughter cells would have a total 33 x 2 = 66 sister chromatids at prophase II.
Since meiosis II maintains the chromosome number, each sperm cell formed by the end of meiosis II would have 33 chromosomes.
Answer:
Species that are broadly distributed are less likely to go extinct than those that occupy a small area or whose habitat is disjointed.
