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Gelneren [198K]
3 years ago
11

You have isolated a mutant strain of Bacillus subtilis (which you designate wimP) whose endospores can be killed by boiling wate

r. When you analyze the endospores produced by this strain, you find that compared to endospores produced by the parent (a wild-type strain), the wimP spores have significantly:
A. elevated amounts of germination factors.

B. reduced amounts of small acid-soluble proteins.

C. reduced amounts of germination factors.

D. lower amounts of spore coat proteins.

E. higher water content.
Biology
1 answer:
BARSIC [14]3 years ago
7 0

Answer:

The correct answer is B. reduced amounts of small acid-soluble proteins.

Explanation:

Spores of Bacillus subtilis contains very small amount of small acid-soluble proteins which only comprise of 20% of the total spore core protein. These small acid-soluble proteins provides resistance against chemicals, heat or UV radiation.

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Jasmine's body responds with a mechanism of heat loss, such as sweating and evaporation, to reduce her internal body temperature and recover homeostasis.

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The human is a homeotherm organism, with a constant body temperature that is between 36.5 and 37 °C. To maintain thermal homeostasis uses several mechanisms.

In the case of Jasmine, the raise of the body temperature, with the exercise, to 38°C stimulates sweat production and its body surface becomes moist. With the evaporation of sweat, body temperature normalizes, since this process involves heat loss.

Also, a voluntary mechanism to lower the temperature is to remove the clothes and remain in a cool environment.

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