The sequence is decreasing by 3 each time
So the formula would be y =27-3(x-1)
Plug in 43
Y =27-3(43-1)
Y = 27-3(42)
Y = 27-126
Y = -99
The 43rd term of the sequence would be -99
Hope this helps :)
Answer:
7 years 11 months
Step-by-step explanation:
The future value formula for the value of a principal P invested at annual rate r compounded n times yearly for t years is ...
FV = P(1 +r/n)^(nt)
For the given numbers, we want to find t:
6000 = 3700(1 +.062/2)^(2t)
Dividing by 3700 and taking the logarithm, we get ...
6000/3700 = 1.031^(2t)
log(60/37) = 2t·log(1.031)
Dividing by the coefficient of t gives ...
t = log(60/37)/(2log(1.031)) ≈ 7.92 . . . . . years
It will take about 7 years 11 months for the investment to grow to $6000.
The number of different ways to distribute m indistinguishable balls into n
distinguishable urns is given by C(m+n-1,n-1).
For example, the number of ways 6 ball can be placed in 7 boxes is given by C(6+7-1, 7-1) = C(12, 6) = 924 ways.
