Sin 2x - sin x=0
Using the trigonometric identity: sin 2x=2 sinx cosx
2 sinx cosx - sinx =0
Common factor sinx
sinx ( 2 cosx -1)=0
Two options:
1) sinx=0
on the interval [0,2π), the sinx=0 for x=0 and x=<span>π=3.1416→x=3.14
2) 2 cosx - 1=0
Solving for cosx
2 cosx-1+1=0+1
2 cosx = 1
Dividing by 2 both sides of the equation:
(2 cosx)/2=1/2
cosx=1/2
cosx is positive in first and fourth quadrant:
First quadrant cosx=1/2→x=cos^(-1) (1/2)→x=</span><span>π/3=3.1416/3→x=1.05
Fourth quadrant: x=</span>2π-π/3=(6π-π)/3→x=5<span>π/3=5(3.1416)/3→x=5.24
Answer: Solutions: x=0, 1.05, 3.14, and 5.24</span>
Answer:
$265
Step-by-step explanation:
You add $435 and $625 and get $1060 dived that by four and you get
The answer is b 14/3.
Hope this helps!
Answer: Your answer is D
Step-by-step explanation: pls mark me as brainiest and 7 x 3 = 21 or 21 / 3 = 7
Answer:
y = 3/7x + 51
Step-by-step explanation:
y = 3/7x + 11 is parallel to the line so it means that both of their gradient are same so:
y = mx + c
m= gradient point = (-21 , 42)
= 3/7
now we sub the m and the point into the formula which is y= mx+c because we should find the c first then we can find the equation of the line:
42 = 3/7 (-21) + c
42 = -9 + c
42 + 9 = c
51 = c
c = 51
now you hv to rewrite again the equation become y= 3/7x + 51
So now your final answer is : y = 3/7x +51
