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Darina [25.2K]
3 years ago
14

The perimeters of the triangles shown below are equal

Mathematics
2 answers:
natulia [17]3 years ago
8 0

Answer:

x=19

Step-by-step explanation:

The perimeter of a shape is the sum of all of its side lengths. Therefore, the perimeter of the first triangle is x-7+x-7+x-7=3x-21 and the perimeter of the second triangle is 9+15+12=36.

We are given that the perimeters of the triangles are equal, so 3x-21 equals 36. As an equation, that would be 3x-21=36. Solving for x, we get:

3x-21=36

3x=57 (Add 21 to both sides of the equation to isolate x)

x=19 (Divide both sides of the equation by 3 to get rid of x's coefficient)

Hope this helps!

Naya [18.7K]3 years ago
6 0

Answer:

x=19

Step-by-step explanation:

The perimeter of the right triangle is

P=9+12+15 =36

The perimeter of the left triangle is

P =x-7+ x-7+ x-7 = 3x-21

Set them equal

36 = 3x-21

Add 21 to each side

36+21 = 3x-21+21

57 = 3x

Divide each side by 3

57/3 = 3x/3

19 =x

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