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Anit [1.1K]
3 years ago
13

F(x)=49 range and domain

Mathematics
1 answer:
SpyIntel [72]3 years ago
7 0

Answer:

here domain is x and range is 49

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Find the quotient of 1 1/4 and 3 1/2 . Express your answer in simplest form.
tino4ka555 [31]

Answer:

8/35

Step-by-step explanation:

1 1/4 = 5/4

3 1/2 = 7/2

5/4 × 7/2

Find the reciprocal. (flip numerator and denomimator)

4/5 × 2/7 = 8/35

4 0
3 years ago
HELPP FAST!! Will mark brainliest
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Answer:

No

Step-by-step explanation:

Because it is not going up by the same amount everytime

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Dawson says that the expression (2 4/10+8 4/5(
Katen [24]

Answer:

56/5

Step-by-step explanation:

2 4/10=24/10

8 4/5=44/5

24/10+44/5=24/10+88/10=112/10=56/5

7 0
3 years ago
Consider the expression 6n2 + 2n + 3 . What is the coefficient of n?
ad-work [718]

Answer:

Step-by-step explanation:

2

The coefficient is the number in front of the variable.

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6 0
3 years ago
Tensile-strength tests were carried out on two different grades of wire rod. Grade 1 has 10 observations yielding a sample mean
LuckyWell [14K]

Answer:

t = \frac{1085-1034}{\sqrt{\frac{52^2}{10} +\frac{61^2}{15}}} = 2.240

df = n_1 +n_2 -2 = 10+15-2= 23

p_v = 2*P(t_{23} >2.240) = 0.035

Since the p value is lower than the significance level we have enough evidence to conclude that the true means are different at 5% of significance

Step-by-step explanation:

Data given

\bar X_1 = 1085 sample mean for group 1

\bar X_2 = 1034 sample mean for group 2

n_1 = 10 sample size for group 1

n_2 = 15 sample size for group 2

s_1 = 52 sample deviation for group 1

s_2 = 61 sample deviation for group 2

Solution

We want to check if the two means are equal so then the system of hypothesis are:

Null hypothesis: \mu_1= \mu_2

Alternative hypothesis: \mu_1 \neq \mu_2

And the statistic is given by:

t = \frac{\bar X_1 -\bar X_2}{\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}}

And replacing we got:

t = \frac{1085-1034}{\sqrt{\frac{52^2}{10} +\frac{61^2}{15}}} = 2.240

The degrees of freedom are given by:

df = n_1 +n_2 -2 = 10+15-2= 23

And the p value would be:

p_v = 2*P(t_{23} >2.240) = 0.035

Since the p value is lower than the significance level we have enough evidence to conclude that the true means are different at 5% of significance

8 0
3 years ago
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