Write the equation of the line passing through point (-2

during a 3 day event a total of 7,458 people attended. if the same people of people attended each day, how many people attended

s344n2d4d5 [400]

Answer... I don't know if this is correct but here it is.

1864.5

Hope this helps! Brainliest would be appreciated!

4 0

4 years ago

Read 2 more answers

Find the mean, median, and mode(s) of the data set. 3, 41 , 11, 3, 11, 5, 10

Alex_Xolod [135]

mean=12

median=10

mode=3 and 11

3 0

3 years ago

Read 2 more answers

A rectangular parking lot has an area of 15,000 feet squared, the length is 20 feet more than the width. Find the dimensions

faust18 [17]

Dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet

<h3>Solution:</h3>

Given that

Area of rectangular parking lot = 15000 square feet

Length is 20 feet more than the width.

Need to find the dimensions of rectangular parking lot.

Let assume width of the rectangular parking lot in feet be represented by variable "x"

As Length is 20 feet more than the width,

so length of rectangular parking plot = 20 + width of the rectangular parking plot

=> length of rectangular parking plot = 20 + x = x + 20

The area of rectangle is given as:

$\text {Area of rectangle }=length \times width$

Area of rectangular parking lot = length of rectangular parking plot $\times$ width of the rectangular parking

$\begin{array}{l}{=(x+20) \times (x)} \\\\ {\Rightarrow \text { Area of rectangular parking lot }=x^{2}+20 x}\end{array}$

But it is given that Area of rectangular parking lot = 15000 square feet

$\begin{array}{l}{=>x^{2}+20 x=15000} \\\\ {=>x^{2}+20 x-15000=0}\end{array}$

Solving the above quadratic equation using quadratic formula

General form of quadratic equation is

${ax^{2}+\mathrm{b} x+\mathrm{c}=0$

And quadratic formula for getting roots of quadratic equation is

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

In our case b = 20, a = 1 and c = -15000

Calculating roots of the equation we get

$\begin{array}{l}{x=\frac{-(20) \pm \sqrt{(20)^{2}-4(1)(-15000)}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{400+60000}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{60400}}{2}} \\\\ {x=\frac{-(20) \pm 245.764}{2 \times 1}}\end{array}$

$\begin{array}{l}{=>x=\frac{-(20)+245.764}{2 \times 1} \text { or } x=\frac{-(20)-245.764}{2 \times 1}} \\\\ {=>x=\frac{225.764}{2} \text { or } x=\frac{-265.764}{2}} \\\\ {=>x=112.882 \text { or } x=-132.882}\end{array}$

As variable x represents width of the rectangular parking lot, it cannot be negative.

=> Width of the rectangular parking lot "x" = 112.882 feet

=> Length of the rectangular parking lot = x + 20 = 112.882 + 20 = 132.882

Hence can conclude that dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet.

3 0

3 years ago

You invest $2000 in an account that pays 2.7% interest compunded annually. If you make no payments into the account, what will t

vaieri [72.5K]

Answer:

Annually: 2,610.56

Monthly: 2,619.13

Step-by-step explanation:

3 0

3 years ago

Jean has 1/8 cup of applesauce for her recipe. She needs 5/8 cup more. How much applesauce is needed for the recipe?

Anestetic [448]

2/4 this is a half also known as 1/2 Hope this helps!!!!!!!!!!!!!!!!!!!!!!!!

4 0

3 years ago

Write the equation of the line passing through point (-2 - 2) with a slope of -1