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Nonamiya [84]
3 years ago
7

Elizabeth has a lot of jewelry. She has four times as many earrings as watches but half the number of necklaces as earrings. Eli

zabeth has the same number of necklaces as bracelets. If Elizabeth has 117 pieces of jewelry, has many earrings does she have
Mathematics
1 answer:
evablogger [386]3 years ago
7 0
Given:
Total number of pieces: 117
watch = x
earrings = four times as many earring as watches = 4x
necklaces = half the number of necklaces as earrings = 1/2 * 4x = 2x
bracelets = necklaces = 2x

x + 4x + 2x + 2x = 117
9x = 117
x = 117/9
x = 13

watches: x = 13
earrings: 4x = 4(13) = 52
necklaces: 2x = 2(13) = 26
bracelets: 2x = 2(13) = 26

13 + 52 + 26 + 26 = 117

There are 13 watches, 52 earrings, 26 necklaces, and 26 bracelets.
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Find the center and radius of the sphere whose equation is given by x2+y2+z2−2x−4y+8z+17=0x2+y2+z2−2x−4y+8z+17=0.
Vedmedyk [2.9K]
We know that
the equation of a sphere is
(x-h)²+(y-k)²+(z-l)²=r²
where (h,k,l) is the center and r is the radius

we have
x²+y²+z²<span>−2x−4y+8z+17=0
</span>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(x²+2x)+(y²-4y)+(z²+8z)=-17
<span>Complete the square. Remember to balance the equation by adding the same constants to each side
</span>(x²+2x+1)+(y²-4y+4)+(z²+8z+16)=-17+1+4+16
(x²+2x+1)+(y²-4y+4)+(z²+8z+16)=4

Rewrite as perfect squares

(x+1)²+(y-2²)+(z+4)²=4

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4 0
3 years ago
Given the linear programming problem, use the method of corners to determine where the minimum occurs and give the minimum value
algol [13]

Answer:

Minimum value of function C=x+10y is 63 occurs at point (3,6).

Step-by-step explanation:

To minimize :

                                   C=x+10y

Subject to constraints:

                                   x\leq 3---(1)\\y\leq 9---(2)\\x+y\geq 9----(3)\\x\geq 0\\y\geq 0

Eq (1) is in blue in figure attached and region satisfying (1) is on left of blue line

Eq (2) is in green in figure attached and region satisfying (2) is below the green line

Considering x+y\geq 9, corresponding coordinates point to draw line are (0,9) and (9,0).

Eq (3) makes line in orange in figure attached and region satisfying (3) is above the orange line

Feasible region is in triangle ABC with common points A(0,9), B(3,9) and C(3,6)

Now calculate the value of function to be minimized at each of these points.

                                    C=x+10y

at A(0,9)

                                     C=0+10(9)\\C=90

at B(3,9)

                                     C=3+10(9)\\C=93

at C(3,6)

                                     C=3+10(6)\\C=63

Minimum value of function C=x+10y is 63 occurs at point C (3,6).

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Answer:

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Step-by-step explanation:

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