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lesya [120]
3 years ago
8

3/4 part of a rope is 150m. find the length of 7/10 part of the rope

Mathematics
1 answer:
a_sh-v [17]3 years ago
6 0

Answer:

140m

Step-by-step explanation:

3/4 = .75

x/.7 = 150/.75

multiply both sides by .7

x = 150/.75 * .7

x = 140m

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Answer:

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3 years ago
Farmer Company purchased equipment on January 1, Year 1 for $82,000. The equipment is estimated to have a 5-year life and a salv
aalyn [17]

Answer:

option (a) $6,240

Step-by-step explanation:

Given:

Purchasing cost of the equipment = $82,000

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Salvage value = $4,000

Revised expected life = 8 years

Now,

Depreciation per year = \frac{\textup{82,000-4,000}}{\textup{5}}

therefore,

The accumulated Depreciation at the beginning of year 4

= Annual depreciation × years passed

= 15,600 × 3

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The remaining life = Revised estimated life - Years passed

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= 5 years

therefore,

Depreciation expense =\frac{\textup{book value at the beginning of year 4 - salvage value}}{\textup{Revised estimated life}}

= \frac{\textup{35,200  - 4000}}{\textup{5}}

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The correct answer is option (a) $6,240

7 0
3 years ago
Solve for y , what is 9x+3y=4 ??
lora16 [44]
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Answer:

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\\  \\

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\\  \\

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6 0
3 years ago
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