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3 years ago

Answer this question to get marked as barinliest!!!!!

Mathematics

2 answers:

Gre4nikov [31]3 years ago

5 0

Answer:

32 degrees

Step-by-step explanation:

114° - 82° = r°

=> r = 32°

kykrilka [37]3 years ago

4 0

Answer:

Step-by-step explanation:

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Algebra 2 need a lil help

babymother [125]

Answer:

Step-by-step explanation:

The zeroes or x intercepts are when the line crosses through the x-axis.

In this case you should only have one being (1) because the line only passes the x-axis once. Also by real zeroes it means non -5i #s so nothing with an (i) for imaginary #'s.

Hope this helps.

8 0

3 years ago

Read 2 more answers

The combined weight of 2 identical dice, 5 identical balls and 4 identical marbles was 260 grams. The combined weight of one die

olya-2409 [2.1K]

Answer:

The total weight of one die, one ball, and one marble is 75 grams.

Step-by-step explanation:

Consider the provided information.

Let d represents the number of dice, b represents the number of balls and m represents the number of marbles.

So according to the question.

The combined weight of 2 identical dice, 5 identical balls and 4 identical marbles was 260 grams.

$2d+5b+4m=260$ ....(1)

The combined weight of one die and one marble was 55 grams.

$d+m=55$

$m=55-d$ ....(2)

3 balls weighed the same as two dice.

$3b=2d$

Multiply both sides by 5 and divide by 3.

$5b=\frac{10}{3}d$ .....(3)

Now put the value of equation 2 and 3 in equation 1.

$2d+\frac{10}{3}d+4(55-d)=260$

$2d+\frac{10}{3}d+220-4d=260$

$\frac{6d+10d-12d}{3}=40$

$4d=120$

$d=30$

Put d=30 in equation 2.

$m=55-30$

$m=25$

Put d=30 in equation 3.

$5b=\frac{10}{3}\times 30$

$5b=100$

$b=20$

The total weight (in grams) of one die, one ball, and one marble is:

$d+m+b=25+20+30$

$d+m+b=75$

The total weight of one die, one ball, and one marble is 75 grams.

8 0

3 years ago

P（x）=x³-5x²+4x-3 D（x）=x-1

snow_tiger [21]

Answer:

hope this helps.

btw I used synthetic decision method

7 0

3 years ago

the Andersons kept track of the time they spent watching television. Part A wich bar diagram represents the number of hours the

DENIUS [597]

Part A:

Part B:

$\begin{gathered} 4\frac{5}{6}=\frac{29}{6} \\ 3\frac{4}{6}=\frac{11}{3} \\ so\colon \\ \frac{29}{6}+\frac{11}{3}=\frac{17}{2}=8\frac{3}{6} \end{gathered}$

Part C:

$\begin{gathered} 3\frac{1}{6}=\frac{19}{6} \\ 2\frac{3}{6}=\frac{15}{6} \\ so\colon \\ \frac{29}{6}+\frac{11}{3}+\frac{19}{6}+\frac{15}{6}=\frac{85}{6}=14\frac{1}{6} \end{gathered}$

Part D:

$\frac{17}{2}-\frac{17}{3}=\frac{17}{6}=2\frac{5}{6}_{}$

4 0

1 year ago

Need help :( . . . . I need to pass it tomorrow..

koban [17]

Answer:

across

3. 6x

4. 14mn

5. 31

6. 25b

9. 5abc

down

1. 3y

4. 19m

5. 3m2np2

7. 7y

8. 9x

Step-by-step explanation:

hope this helps

4 0

2 years ago