Ask question

Ask question

All categories

sergeinik [125]

3 years ago

7

Which equation represents the situation shown in the bar diagram?

1 answer:

Elis [28]3 years ago

4 0

Answer:

try that it should help you with you question

Step-by-step explanation:

https://www.khanacademy.org/math/cc-2nd-grade-math/x3184e0ec:data/cc-2nd-bar-graphs/v/creating-bar-charts-1

You might be interested in

What is 0.78 reapeating as a simplified fraction

lina2011 [118]

Is the 8 repeating or 78

If just 8: 71/90

If 78: 78/99

4 0

3 years ago

- When Brianna's first CD sold a million copies, her record label

Pie

Answer:

Each person received $1,250

6 0

3 years ago

you invest $750 in a savings account that pays 1.5% annual interest.Write a recursive and a explicit formula to represent to sit

Natasha_Volkova [10]

750x 0.015= $11.25 each month
11.25x12= 135

3 0

3 years ago

Blake and James are planning to go on a trip. Blake already has some money saved. She earns $96 more by working overtime. James

rosijanka [135]

Blake saved $\bold{\$ 433.80}$

Option - A

<u>SOLUTION: </u>

Given, Blake and James are planning to go on a trip.

Blake already has some money saved.

Let the amount saved by Blake be $\$ n$ .

She earns $\$96$ more by working overtime.

Then, total amount by Blake $=\$(n+96)$

James has $\$ 53$ more than 4 times the amount of money that Blake has saved.

Then, total amount by James will be $\$ 53+4 \times \$ n=\$(4 n+53)$

If they have $\$2,318$ in all, we have to find how much money had Blake originally saved

Now, total amount = $\$2318$

$\begin{array}{l}{\rightarrow \text { Amount by Blake }+\text { amount by James }=2318} \\\\ {\rightarrow \mathrm{n}+96+4 \mathrm{n}+53=2318 \rightarrow 5 \mathrm{n}+149=2318 \rightarrow 5 \mathrm{n}=2318-149 \rightarrow 5 \mathrm{n}=2169 \rightarrow \mathrm{n}=433.8}\end{array}$

7 0

4 years ago

Find the complex fourth roots \[-\sqrt{3}+\iota \] in polar form.

____ [38]

Let $z=-\sqrt3+i$ . Then

$|z|=\sqrt{(-\sqrt3)^2+1^2}=2$

$z$ lies in the second quadrant, so

$\arg z=\pi+\tan^{-1}\left(-\dfrac1{\sqrt3}\right)=\dfrac{5\pi}6$

So we have

$z=2e^{i5\pi/6}$

and the fourth roots of $z$ are

$2^{1/4}e^{i(5\pi/6+k\pi)/4}$

where $k\in\{0,1,2,3\}$ . In particular, they are

$2^{1/4}e^{i(5\pi/6)/4}=2^{1/4}e^{i5\pi/24}$

$2^{1/4}e^{i(5\pi/6+2\pi)/4}=2^{1/4}e^{i17\pi/24}$

$2^{1/4}e^{i(5\pi/6+4\pi)/4}=2^{1/4}e^{i29\pi/24}$

$2^{1/4}e^{i(5\pi/6+6\pi)/4}=2^{1/4}e^{i41\pi/24}$

7 0

3 years ago