Math help meeeeeeeeee
1 answer:
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Answer: Their equations have different y-intercept but the same slope
Step-by-step explanation:
Since, the slope of the line passes through the points (2002,p) and (2011,q) is,
Similarly, the slope of the line asses through the points (2,p) and (11,q) is,
Since,
Hence, both line have the same slope.
Now, the equation of the line one having slope and passes through the point (2002,p) is,
Put x = 0 in the above equation,
We get,
The y-intercept of the line one is
Also, the equation of second line having slope and passes through the point (2,p)
Put x = 0 in the above equation,
We get,
The y-intercept of the line one is
Thus, both line have the different y-intercepts.
⇒ Third option is correct.
<h3>Answer: Choice D. 
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The red angle markers show those two angles are congruent. That's one "A" of "ASA". The S refers to a congruent pair of sides. We don't have any tickmarks to indicate congruent pairs; however, we do know that QR = QR is a shared side that overlaps (reflexive theorem). So this is the "S" in "ASA".
The thing missing is the angle Q of the top triangle, and also of the bottom triangle as well. If we know those two angles are congruent, then we have enough info to use ASA. More specifically, if we know that , then we can use ASA.
One thing to notice is that the other answer choices involve side lengths and not angles. This implies that if A, B or C were one of the answers, then we would have something like SAS or SSS. But instead we want ASA. So we can immediately rule choices A,B, and C out.
Answer:
see explanation
Step-by-step explanation:
Given
4 - 5a² + 1 = 0
Use the substitution u = a², then equation is
4u² - 5u + 1 = 0
Consider the product of the coefficient of the u² term and the constant term
product = 4 × 1 = 4 and sum = - 5
The factors are - 4 and - 1
Use these factors to split the u- term
4u² - 4u - u + 1 = 0 ( factor the first/second and third/fourth terms )
4u(u - 1) - 1(u - 1) = 0 ← factor out (u - 1) from each term
(u - 1)(4u - 1) = 0
Equate each factor to zero and solve for u
u - 1 = 0 ⇒ u = 1
4u - 1 = 0 ⇒ 4u = 1 ⇒ u =
Convert u back into terms of a, that is
a² = 1 ⇒ a = ± 1
a² = ⇒ a = ±
Solutions are a = ± 1 , a = ±