7/10 = 70%
21/25 = 84%
3/5 = 60%
18/25 = 72%
The distance travelled by the car will be 3.6km in 2 minutes.
<u>Explanation:</u>
Given:
Speed, s = 108 km/hr
s in km/min = ?
1 hr = 60 min
So,
108 km/hr = 
= 1.8 km/min
time, t = 2 min
Distance, d = ?
We know:
distance = speed X time

Therefore, the distance travelled by the car will be 3.6km in 2 minutes.
(a) Let
denote the amount of sugar in the tank at time
. The tank starts with only pure water, so
.
(b) Sugar flows in at a rate of
(0.07 kg/L) * (7 L/min) = 0.49 kg/min = 49/100 kg/min
and flows out at a rate of
(<em>A(t)</em>/1080 kg/L) * (7 L/min) = 7<em>A(t)</em>/1080 kg/min
so that the net rate of change of
is governed by the ODE,

or

Multiply both sides by the integrating factor
to condense the left side into the derivative of a product:


Integrate both sides:


Solve for
:

Given that
, we find

so that the amount of sugar at any time
is

(c) As
, the exponential term converges to 0 and we're left with

or 75.6 kg of sugar.
16 ways. 4 times 4 equals 16.