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kkurt [141]
3 years ago
8

Write an equation of a line that passes through (-6,4) and is PERPENDICULAR to y=3x-11

Mathematics
2 answers:
tester [92]3 years ago
3 0

Answer:

y = -1/3x + 2

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS
  • Equality Properties

<u>Algebra I</u>

Perpendicular lines have the negative reciprocal slope of the original.

Slope-Intercept Form: y = mx + b

  • m - slope
  • b - y-intercept

Step-by-step explanation:

<u>Step 1: Define</u>

y = 3x - 11

Point (-6, 4)

<u>Step 2: Find slope </u><em><u>m</u></em>

Negative Reciprocal of 3 = -1/3

<u>Step 3: Define</u>

y = -1/3x + b

<u>Step 4: Find y-intercept </u><u><em>b</em></u>

  1. Substitute in point:                    4 = -1/3(-6) + b
  2. Multiply:                                      4 = 2 + b
  3. Subtract 2 on both sides:         2 = b
  4. Rewrite:                                      b = 2

<u>Step 5: Write perpendicular linear equation</u>

y = -1/3x + 2

Inessa05 [86]3 years ago
3 0

Answer:

     b = 2

Step-by-step explanation:

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