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3 years ago

Modeling real-world problems with one-step equations

Mathematics

2 answers:

Stels [109]3 years ago

7 0

Answer:

Think of an equation that works, then come up with a real-world situation you might need it

Step-by-step explanation:

BARSIC [14]3 years ago

4 0

Think of an equation that works, then come up with a real-world situation you might need it

Also, the other answer literally copied and pasted my answer lol

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hope it helps

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John has six bills of paper money in the following denominations $1, $5, $10, $20, $50, and $100. If he selects 3 bills at a tim

densk [106]

<span>the probability will be 0.55</span>

4 0

3 years ago

A stainless steel patio heater is a square pyramid. The length of one side of the base is 22.4 in. The slant height of the pyram

mrs_skeptik [129]

Answer:

93.03 in

Step-by-step explanation:

Height of square pyramid: √slant height² - (1/2 base side length)²

SH = √93.7² - 11.2² = 93.03

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3 years ago

The measure of AngleRST can be represented by the expression (6x + 12)°. Three lines extend from point S. The space between line

DochEvi [55]

Answer:The measure of angle RST is 120\°

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

m<RST=(6x+12)\° -----> equation A

m<RST=78\°+(3x-12)\° -----> equation B

equate equation A and equation B

(6x+12)\°=78\°+(3x-12)\°

8 0

3 years ago

HELP WITH THIS QUESTION PLEASE!!

svetlana [45]

m<PQS = m<SQR

4y - 10 = 2y + 10

2y = 20

y = 10

m<PQR = m<PQS + m<SQR

= 4y - 10 + 2y + 10

= 6y

= 6•10

= 60

3 0

3 years ago

A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly at the 450 gram setting. It

Arturiano [62]

Answer:

Test statistic = -2.25

P-value = 0.0199

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 450 gram

Sample mean, $\bar{x}$ = 441 grams

Sample size, n = 16

Alpha, α = 0.05

Sample variance = 256

$\sigma^2 = 256\\\sigma = \sqrt{256} = 16$

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 450\text{ grams}\\H_A: \mu < 450\text{ grams}$

We use one-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{441 - 450}{\frac{16}{\sqrt{16}} } = -2.25$

Now,

Degree of freedom =

$=n-1 = 16-1=15$

We can calculate the p-value from the table as:

P-value = 0.0199

Conclusion:

Since the p-value is smaller than the significance level we fail to accept the null hypothesis and reject it.

Thus, there is enough evidence to support the claim that the machine is under filling the bags .

5 0

3 years ago