Ask question

Ask question

All categories

2 years ago

8

I am a trapezium, identify my properties from the following:

1 answer:

vredina [299]2 years ago

8 0

a. my opposite sides are parallel

FALSE. Only the basis sides are parallel.

<u>b. I am a quadrilateral </u>

TRUE. A trapezium has 4 sides.

c. I have all the sides equal

FALSE. The trapezium is a special shape in that it does not, unlike the square or rectangle, have to have any equal side lengths.

You might be interested in

PLEASE HELP ILL GIVE A BRAINLIEST

zavuch27 [327]

Guessing you meant by a factor of 3... not 13 since none of the solutions are anywhere close to that.

to compress is to smoosh.
It's the equation of a line. If you smoosh it vertically the line becomes flatter and the slope smaller.

Essentially g(x) = 3f(x)
3y = 12x + 6
y = (12/3)x + 6/3
y = 4x + 2

8 0

2 years ago

5/8 divided by 1 1/3 equals?

Hitman42 [59]

Step-by-step explanation:

5/8 x 3/11 = answer

Keep change flip

5 0

2 years ago

Read 2 more answers

The function A=A_oe^{-0.01155x} A = A o e − 0.01155 x models the amount in pounds of a particular radioactive material stored in

vivado [14]

They are essentially asking us to solve:

$357=900e^{-0.01155x} \implies\\ \frac{357}{900}=e^{-0.01155x} \implies\\ \ln{\frac{357}{900}}=-0.01155x \implies \\ x\approx 80.1$

Solving this equation for x tells us that it will take around 80.1 years for the materials in the vault to reduce to 357 pounds.

4 0

2 years ago

Read 2 more answers

How many solutions does the equation - 8x + 5 = - 8x + 4 have

KiRa [710]

$- 8x + 5 = - 8x + 4 \\ - 8x = - 8x + 4 - 5 \\ - 8x = - 8x - 1 \\ 0 = - 1(false)$

we don't have solutions !!

3 0

2 years ago

A roll of steel is manufactured on a processing line. The anticipated number of defects in a 10-foot segment of this roll is two

Vikentia [17]

Answer:

the probability of no defects in 10 feet of steel = 0.1353

Step-by-step explanation:

GIven that:

A roll of steel is manufactured on a processing line. The anticipated number of defects in a 10-foot segment of this roll is two.

Let consider β to be the average value for defecting

So;

β = 2

Assuming Y to be the random variable which signifies the anticipated number of defects in a 10-foot segment of this roll.

Thus, y follows a poisson distribution as number of defect is infinite with the average value of β = 2

i.e

$Y \sim P( \beta = 2)$

the probability mass function can be represented as follows:

$\mathtt{P(y) = \dfrac{e^{- \beta} \ \beta^ \ y}{y!}}$

where;

y = 0,1,2,3 ...

Hence, the probability of no defects in 10 feet of steel

y = 0

$\mathtt{P(y =0) = \dfrac{e^{- 2} \ 2^ \ 0}{0!}}$

$\mathtt{P(y =0) = \dfrac{0.1353 \times 1}{1}}$

P(y =0) = 0.1353

4 0

2 years ago