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3 years ago

Rational number and irrational number

Mathematics

2 answers:

vodka [1.7K]3 years ago

7 0

This doesn’t give me anything like do you need the definition or what

kati45 [8]3 years ago

6 0

Answer:

Rational numbers are the numbers that can be expressed in the form of a ratio (P/Q & Q≠0).

Irrational numbers cannot be expressed as a fraction. But both the numbers are real numbers and can be represented in a number line.

Step-by-step explanation:

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16 + b^2 = 25. -16
B^2 = 9
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The other leg is 3cm

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What is rotational symmetry

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3 years ago

If h = 3.5u, what is the value of h when u = 17?<br> Give any decimal answers to 1 d.p.

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3 0

2 years ago

Read 2 more answers

Please help!!As soon as possible!!

pychu [463]

Answer: Their equations have different y-intercept but the same slope

Step-by-step explanation:

Since, the slope of the line passes through the points (2002,p) and (2011,q) is,

$m_1 = \frac{q-p}{2011-2002} = \frac{q-p}{9}$

Similarly, the slope of the line asses through the points (2,p) and (11,q) is,

$m_2 = \frac{q-p}{11-2} = \frac{q-p}{9}$

Since, $m_1 = m_2$

Hence, both line have the same slope.

Now, the equation of the line one having slope $m_1$ and passes through the point (2002,p) is,

$y - p = \frac{q-p}{9}(x-2002)$

Put x = 0 in the above equation,

We get, $y = \frac{2000(p-q)}{9}+p$

The y-intercept of the line one is $(0, \frac{2000(p-q)}{9}+p)$

Also, the equation of second line having slope $m_2$ and passes through the point (2,p)

$y-p=\frac{q-p}{9}(x-2)$

Put x = 0 in the above equation,

We get, $y = \frac{2(p-q)}{9}+p$

The y-intercept of the line one is $(0, \frac{2(p-q)}{9}+p)$

Thus, both line have the different y-intercepts.

⇒ Third option is correct.

6 0

3 years ago

Rational number and irrational number ​

Rational number and irrational number