All categories

3 years ago

Which of the following is equivalent to the polynomial below ? X^2-8x+19

Mathematics

2 answers:

andrey2020 [161]3 years ago

7 0

Answer:

C, I believe.

Ahat [919]3 years ago

3 0

Have a good night!

Hope this helped!

You might be interested in

A taxi costs 3 dollars plus an additional 2 dollars per mile traveled \. You spent exactly $20 on taxi which includes the one do

umka2103 [35]

Answer:

8 miles

Step-by-step explanation:

3+2x+1=20

2x+4=20

2x=16

x=8

8 miles.

Hope this helps!

Merry Christmas!

7 0

3 years ago

Read 2 more answers

If the conditional statement "If you live in Boise, then you live in Idaho," is true, then which other form of the conditional m

blsea [12.9K]

Since both statements are true, then it is contrapositive

7 0

3 years ago

MAFS.5.NF.2.5b

Assoli18 [71]

Answer:

Step-by-step explanation:

See attachment.

8 0

3 years ago

What is the approximate area of the shaded sector in the circle below

melisa1 [442]

First to find the area the formula is A=pi(r^2)
so plug in the numbers A= (3.14)(4.5)(4.5)= 63.62 is the total area

150*63.62=9543 9543/360=26.5

So the answer is 26.5 cm ^2

8 0

4 years ago

Read 2 more answers

While visiting the Albert Michelson exhibit at Clark University, you notice that a chandelier (which looks remarkably like a sim

labwork [276]

Answer:

a) $F=0.16Hz$

b) $\omega=1rad/s$

c) $L=9.54m$

d) $g=9.46m/s^2$

Step-by-step explanation:

From the question we are told that:

Time $T =6.2$

Generally the equation for Frequency F is mathematically given by:

$F=\frac{1}{T}$

$F=\frac{1}{6.2}$

$F=0.16Hz$

Generally the equation for Frequency F is mathematically given by:

$\omega=2\pi f$

$\omega=2*314* 0.16$

$\omega=1rad/s$

Generally the equation for Length of Chandelier L is mathematically given by:

Since

$T=2*3.142\sqrt{\frac{L}{g}}$

Therefore

$L=\frac{gT^2}{4 \pi^2}$

$L=\frac{9.8*(6.2)^2}{4 \pi^2}$

$L=9.54m$

Since

Michelson exhibit except this one swings back and forth 0.11 seconds slower

Therefore

$T'=T+0.11$

$T'=6.31$

Generally the equation for acceleration due to gravity g is mathematically given by:

$g = \frac{4\pi ^2L}{( T')}^2$

$g = \frac{4\pi ^2L\*9.54}{( 6.31 s )}^2$

$g=9.46m/s^2$

4 0

3 years ago