Answer:
Probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
Step-by-step explanation:
We are given that the diameters of ball bearings are distributed normally. The mean diameter is 106 millimeters and the standard deviation is 4 millimeters.
<em>Firstly, Let X = diameters of ball bearings</em>
The z score probability distribution for is given by;
Z = 
~ N(0,1)
where, 
= mean diameter = 106 millimeters
= standard deviation = 4 millimeter
Probability that the diameter of a selected bearing is greater than 111 millimeters is given by = P(X > 111 millimeters)
P(X > 111) = P( > 
) = P(Z > 1.25) = 1 - P(Z 
1.25)
= 1 - 0.89435 = 0.1056
Therefore, probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
Answer:
Step-by-step explanation:
Answer:
FV= 200*(1.07^n)
Step-by-step explanation:
Current population= 200 deer
Growth rate= 7% per year
<u>To calculate the future value of deer in any given years, we need to use the following formula:</u>
<u></u>
FV= PV*(1+g)^n
FV= future value
PV= present value
g= growth rate
n= number of years
FV= 200*(1.07^n)
<u>For example, the population in 5 years:</u>
FV= 200*(1.07^5)
FV= 281
Answer:
Graph B
This is because of the vertical line test. Say you were to draw a vertical line that stretches through the whole graph. If this line you draw passes through more than two points of the same line/function/whatever b is, it is not a function.
Answer:
uh okay I'm just stumbling upon questions like this
